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nordsb [41]
3 years ago
15

Give P(-1, 8) and Q(5,12), and MN is the image of PQ under a translation of T

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
4 0
Coordinates of N are (-55, 6)
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Complete the given diagram by dragging expressions to each leg of the triangle. Then, correctly complete the equation to derive
Nimfa-mama [501]

The equation to derive the distance d is \sqrt{(x2-x1)^2+(y2-y1)^2}. The lengths of the other legs of the given triangle are (y2 - y1) and (x2 - x1).

<h3>What is the formula for calculating the distance between two points?</h3>

Consider the two points (x1, y1) and (x2, y2)

The formula used for calculating the distance between the two points is

distance = \sqrt{(x2-x1)^2+(y2-y1)^2}

<h3>Calculation:</h3>

Given that,

The triangle in the graph has vertices (x1, y1), (x2, y2), and (x2, y1)

Since this triangle makes 90°, it is a right-angled triangle.

Hypotenuse = (x1, y1) to (x2, y2), Adjacent = (x1, y1) to (x2,y1), and Opposite = (x2, y1) to (x2, y2).

Consider the length of the hypotenuse = d

So, using the distance formula, the length of the hypotenuse(d) is,

d = \sqrt{(x2-x1)^2+(y2-y1)^2}

And the lengths of the other two legs of the given triangle are,

Length of the adjacent side: (x1, y1) to (x2,y1)

= \sqrt{(x2-x1)^2+(y1-y1)^2}

= \sqrt{(x2-x1)^2+0}

= (x2-x1)

Length of the opposite side: (x2, y1) to (x2, y2)

= \sqrt{(x2-x2)^2+(y2-y1)^2}

= \sqrt{0+(y2-y1)^2}

= (y2-y1)

Therefore, the derived distances for the given triangle are:

d=\sqrt{(x2-x1)^2+(y2-y1)^2}, (x2 - x1), and (y2 - y1).

Learn more about the distance between two points here:

brainly.com/question/661229

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4 0
2 years ago
Plz help me-7.1(z-1.1)
Elena-2011 [213]

Answer:

<h2>-7.1z +7.81</h2>

Step by step explanation:

- 7.1(z - 1.1)

Multiply each term in paranthesis by -7.1

- 7.1 \times z - 7.1 \times ( - 1.1)

Multiply:

-7.1z + 7.81

Hope this helps...

Good luck on your assignment..

6 0
3 years ago
What is the area of the figure?
natima [27]
The answer is 88 in sq


Explanation: you need to multiply the length a width of each shape then add them all together.
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Fynjy0 [20]

Answer:

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