Answer:
Mechanical advantage = Effort distance/Resistance distance
Effort distance = D - Fulcrum = 0.5 m
Resistance distance = A - Fulcrum = 2.0 m
Then,
Mechanical advantage = 0.5/2 = 0.25
Hockey stick is an example of third class where mechanical advantage is less than one as the speed of the end of point A is critical.
1)
f(x) = x² + 9 g(x) = 24 + 4x
f(4) = (4)² + 9 g(-1) = 24 + 4(-1)
= 16 + 9 = 24 - 4
= 25 = 20

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g(x) = 2ˣ - 4 f(x) = 4x² - 5x - 5
g(6) = 2⁶ - 4 f(-5) = 4(-5)² - 5(-5) - 5
= 64 - 4 = 100 + 25 - 5
= 60 = 120

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f(x) = (3x + 7)²
f(1) = (3(1) + 7)²
= (3 + 7)²
= (10)²
= 100
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3xy + 2x² - y³ ; when x = 6 and y = -2
3(6)(-2) + 2(6)² - (-2)³
-36 + 72 - (-8)
36 + 8
44
X is 3 so 7(3+4)=49 hope that help
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