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2 years ago

5 × ( 1 / 3 + 2 / 5 ) = write your answer as a mixed number

Mathematics

1 answer:

zheka24 [161]2 years ago

7 0

Answer: the answer is 2 and 1/15

Step-by-step explanation:

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Six times the sum of a number and seven is 30. Find the number.

Sedaia [141]

Answer:

x = -2

Step-by-step explanation:

6(x+7)=30

6x+42=30

6x=-12

x=-2

3 0

2 years ago

Read 2 more answers

A. -78 <br> B. 49 <br> C. 53 <br> D. 14

____ [38]

Answer: 49

Step-by-step explanation:

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2 years ago

Write an equation in slope intercept form that is perpendicular to 3x + 2y equals 12 and passes through the point (1,2)

Zigmanuir [339]

Answer:

The equation is y = (2/3)x + (4/3).

Step-by-step explanation:

First, you have to change the equation into slope-intecept formula to find its gradient (slope) :

$3x + 2y = 12$

$2y = - 3x + 12$

$y = - \frac{3}{2}x + 6$

Given that when a line is perpendicular to the other line, their slope value multiplied, will form -1. Next, we have to find the slope for line :

$m1 \times m2 = - 1$

$- \frac{3}{2} \times m2 = - 1$

$m2 = - 1 \div - \frac{3}{2}$

$m2 = \frac{2}{3}$

Lastly, we have to subatitute the x and y values into the equation, to find its intercept value :

$y = \frac{2}{3}x + b$

$let \: x = 1,y = 2$

$2 = \frac{2}{3} (1) + b$

$b = 2 - \frac{2}{3}$

$b = \frac{4}{3}$

$y = \frac{2}{3} x + \frac{4}{3}$

5 0

3 years ago

Selecciona la opción que relaciona con las jergas juveniles

Blizzard [7]

Answer: es la c) 1d,2a,3b,4c

Step-by-step explanation:

5 0

2 years ago

janelle wishes to finance a car for $33,000. the bank's annual interest rate is 3.5%, and she can choose between durations of fi

Harman [31]

Answer:

For a duration of 5 years, Monthly Payment =$600.42

For a duration of 6 years, Monthly Payment =$508.83

Step-by-step explanation:

$P=\dfrac{ar (1+r)^n}{(1+r)^n-1} \\$

where a= Amount to Finance=$33,000

Annual interest rate = 3.5%=0.035

r=Monthly Interest Rate= 0.035 ÷ 12 = $\frac{7}{2400}$

n=number of months to pay

For a duration of 5 years

n=5X12=60 months

$P=\dfrac{ar (1+r)^n}{(1+r)^n-1} \\\\P=\dfrac{33000 X\frac{7}{2400} (1+\frac{7}{2400} )^{60}}{(1+\frac{7}{2400})^{60}-1} \\=\dfrac{96.25 (1.1909)}{1.1909-1}\\=\dfrac{96.25 (1.1909)}{0.1909}\\=\dfrac{114.62}{0.1909}=\$600.42$

For a duration of 6 years

n=6X12=72 months

$P=\dfrac{ar (1+r)^n}{(1+r)^n-1} \\\\P=\dfrac{33000 X\frac{7}{2400} (1+\frac{7}{2400} )^{72}}{(1+\frac{7}{2400})^{72}-1} \\=\dfrac{96.25 (1.2333)}{1.2333-1}\\=\dfrac{96.25 (1.2333)}{0.2333}\\=\dfrac{118.71}{0.2333}=\$508.83$

4 0

2 years ago