Question

What is the equation of the line x–3y=18 in slope-intercept form? Drag and drop the appropriate number, symbol, or variable to each box. xy–18–9–3–13136918+–=

Answer 1

X-3y=18
-3y=-x+18
y=1/3x-6
hope this helps!

Answer 2

We have to find the slope intercept form of the equation of the line x-3y=18.

Slope Intercept Form:

The slope intercept form of any straight line can be written as y = mx + b, where 'm' is the slope of the line and 'b' is the y-intercept. The y-intercept of the line is the value of 'y' at the point where the line crosses the y axis.

For the given line x-3y=18

Adding '3y' on both the sides of the above equation.

$x-3y+3y= 18+3y$

$x=18+3y$

$3y=x-18$

Dividing both sides of the equation by '3'.

$y=\frac{x}{3}-\frac{18}{3}$

$y=\frac{x}{3}-6$

It is the slope intercept form with slope as $\frac{1}{3}$ and 'y' intercept as '-6'.