1) Divide both sides by 2
2x+12^2/3 =16
2) Solve the exponent
2x+12^2/3 =16
(2x+12^2/) ^3/2 =16^3/2 ( raise both sides to power)
2x+12 = 64
3) Subtract 12 from both sides
2x + 12 - 12 = 64-12
2x = 52
4) divide both sides by 2
2x/2 = 52/2
x = 26
Final answer : x = 26
Answer:
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Since the two equations equal y, set them equal to each other.
x-1=-2x+5
From there, solve for x.
First get x on one side, by using the addition property of equality.
x-1=-2x+5
3x-1=5
Isolate x by adding 1.
3x=6
Lastly get x all by itself by dividing each side by 3.
x=2
You can now substitute your x-value, 2, into one of the equations (or both, if you wish; either one will result in the same answer.)
y=x-1
y=2-1
y=1
OR
y=-2x+5
y=-2(2)+5
y=-4+5
y=1
Final answer:
x=2 and y=1
Any questions or anything you would like me to clarify, feel free to ask :)
4x-24y. Basically you distribute 4 to x which makes it 4x and distribute 4 to 6 which multiplies to 24 and you drop y next to it making it 24y
If you distribute the 6(x-2) you would get 6x-12 so zero would equal zero