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Vitek1552 [10]
3 years ago
15

Triangle congruence Which statements are true? Select all that apply.

Mathematics
1 answer:
NISA [10]3 years ago
5 0
All but c are correct so the answer is a b and d
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Parameterize the curve of intersection of the surfaces so that the direction is clockwise when viewed from above. Include a sket
Olegator [25]

Answer:

Answer is attached in images

Step-by-step explanation:

Given:

x+z=1 and

z=4-x^{2} -y^{2}

Now,

1-x=4-x^{2} 2-y^{2} 2\\x^{2} -x+y^{2} \\x^{2} -x+1/4+y^{2} =3\\(x-1/2)^{2} +y^{2} =3+1/4\\(x-1/2)^{2} +y^{2} =(\sqrt(13)/2)^{2}

Which is circle with center (1/2,0) radius

\sqrt{13/2} take, x=1/2+\sqrt{3} /2 cos\alpha \\y=\sqrt{13}/2 sin\alpha        0\leq \alpha \leq 2\pi

Now,

4 0
3 years ago
85 degrees in radians
Sonja [21]
85 degrees=1.484 radians
6 0
3 years ago
Which could be the missing data item for the given set of data if the median of the complete data set is 14?
Goshia [24]
10,10,11,11,12,12,14,15,16,18,18,19

10,10,10,11,11,12,12,14,15,16,18,18,19
10,10,11,11,11,12,12,14,15,16,18,18,19
10,10,11,11,12,12,12,14,15,16,18,18,19
10,10,11,11,12,12,14,15,16,18,18,18,19

I THINK it's D
7 0
3 years ago
A box in the shape of a rectangular prism is approximately 9 inches long,has an equilateral triangle shaped base with side lengt
vfiekz [6]

Answer:

33.75 cubic inches of styrofoam can be placed inside the container.

Step-by-step explanation:

Based on given information, the volume of the prism (V), in cubic inches, is determined by using this formula:

V = \frac{1}{2}\cdot b\cdot h \cdot l (1)

Where:

b - Base of the triangular face, in inches.

h - Height of the triangular face, in inches.

l - Length of the prism, in inches.

If we know that b = 3\,in, h = 2.5\,in and l = 9\,in, then the volume of the prism is:

V = \frac{1}{2}\cdot b\cdot h \cdot l

V = 33.75\,in^{3}

33.75 cubic inches of styrofoam can be placed inside the container.

3 0
3 years ago
Current research indicates that the distribution of the life expectancies of a certain protozoan is normal with a mean of 48 day
irina1246 [14]

Answer:

P ( x_bar ≥ 51 ) = 0.0432

Step-by-step explanation:

Solution:-

- The random variable "X" denotes:

                  X : life expectancies of a certain protozoan

- The variable "X" follows normal distribution.

                  X ~ Norm ( 48 , 10.5^2 )

- A sample of n = 36 days was taken.

- The sample is also modeled to be normally distributed:

                  x ~ Norm ( 48 , ( 10.5 / √n)^2 )

- The sample standard deviation s = 10.5 / √n = 10.5 / √36

                                                      s = 1.75

- We are to investigate the the probability of sample mean x_bar ≥ 51 days:

                 P ( x_bar ≥ 51 )

- Standardize the results, evaluate Z-score:

                 P ( Z ≥ ( x_bar - u ) / s ) =  P ( Z ≥ ( 51 - 48 ) / 1.75 )

                 P ( Z ≥ 1.7142 ).

- Use the standardized normal table and evaluate:

                 P ( Z ≥ 1.7142 ) = 0.0432                  

Hence,      P ( x_bar ≥ 51 ) = 0.0432

5 0
3 years ago
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