Answer:
Answer is attached in images
Step-by-step explanation:
Given:
x+z=1 and

Now,

Which is circle with center (1/2,0) radius
take, 
Now,
10,10,11,11,12,12,14,15,16,18,18,19
10,10,10,11,11,12,12,14,15,16,18,18,19
10,10,11,11,11,12,12,14,15,16,18,18,19
10,10,11,11,12,12,12,14,15,16,18,18,19
10,10,11,11,12,12,14,15,16,18,18,18,19
I THINK it's D
Answer:
33.75 cubic inches of styrofoam can be placed inside the container.
Step-by-step explanation:
Based on given information, the volume of the prism (
), in cubic inches, is determined by using this formula:
(1)
Where:
- Base of the triangular face, in inches.
- Height of the triangular face, in inches.
- Length of the prism, in inches.
If we know that
,
and
, then the volume of the prism is:


33.75 cubic inches of styrofoam can be placed inside the container.
Answer:
P ( x_bar ≥ 51 ) = 0.0432
Step-by-step explanation:
Solution:-
- The random variable "X" denotes:
X : life expectancies of a certain protozoan
- The variable "X" follows normal distribution.
X ~ Norm ( 48 , 10.5^2 )
- A sample of n = 36 days was taken.
- The sample is also modeled to be normally distributed:
x ~ Norm ( 48 , ( 10.5 / √n)^2 )
- The sample standard deviation s = 10.5 / √n = 10.5 / √36
s = 1.75
- We are to investigate the the probability of sample mean x_bar ≥ 51 days:
P ( x_bar ≥ 51 )
- Standardize the results, evaluate Z-score:
P ( Z ≥ ( x_bar - u ) / s ) = P ( Z ≥ ( 51 - 48 ) / 1.75 )
P ( Z ≥ 1.7142 ).
- Use the standardized normal table and evaluate:
P ( Z ≥ 1.7142 ) = 0.0432
Hence, P ( x_bar ≥ 51 ) = 0.0432