Find A + B and 3A using the matrices

Mathematics

1 answer:

hichkok12 [17]3 years ago

6 0

Step-by-step explanation:

$A=\left[\begin{array}{ccc}2&-3\\0&5\\7&-2\end{array}\right] ,\ B=\left[\begin{array}{ccc}1&0\\10&-\frac{1}{2}\\3&1\end{array}\right] \\\\A+B=\left[\begin{array}{ccc}2&-3\\0&5\\7&-2\end{array}\right]+\left[\begin{array}{ccc}1&0\\10&-\frac{1}{2}\\3&1\end{array}\right]\\\\A+B =\left[\begin{array}{ccc}2+1&-3+0\\0+10&5+\left(-\frac{1}{2}\right)\\7+3&-2+1\end{array}\right] \\\\A+B=\left[\begin{array}{ccc}3&-3\\10&4\frac{1}{2}\\10&-1\end{array}\right]$

$3A=3\cdot\left[\begin{array}{ccc}2&-3\\0&5\\7&-2\end{array}\right]\\\\3A=\left[\begin{array}{ccc}3\cdot2&3\cdot(-3)\\3\cdot0&3\cdot5\\3\cdot7&3\cdot(-2)\end{array}\right]\\\\3A=\left[\begin{array}{ccc}6&-9\\0&15\\21&-6\end{array}\right]$

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The girls in Lana’s troop set a goal to sell 1,000 boxes of cookies this year. There are 13 girls in the troop. At least how man

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Answer:

$77$

Step-by-step explanation:

The troop wants to sell a minimum of 1,000 boxes, so we're looking for the smallest number of boxes they can sell and still meet the goal. Since there are 13 girls in the troop, take the ceiling (round up to the nearest whole number) of 1,000 divided by 13:

$\left\lceil \frac{1,000}{13}\right\rceil=\boxed{77}$