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Makovka662 [10]
3 years ago
13

Determine the translation that maps point C(7,5) to point C'(5,5).

Mathematics
1 answer:
sladkih [1.3K]3 years ago
7 0

Answer:

(-2,0)

Step-by-step explanation:

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Need help like now plssss
77julia77 [94]

Answer:

12.56m

<h3>4th answer is correct</h3>

Step-by-step explanation:

\frac{180}{360}  \times 2\pi \: r

\frac{1}{2}  \times 2 \times \pi \times r \\  = 12.56m

5 0
4 years ago
Read 2 more answers
Terry rides her bike for 40 minutes and plays basketball for an hour. How many calories does she burn..? (Per Minute).
Ivan

Answer:

12

Step-by-step explanation:

6 0
3 years ago
A family purchased tickets to a museum and spent a total of $38.00. The family purchased 4 tickets. There was a $1.50 purchasing
Naya [18.7K]

Answer:

4 (x+1.50) = $38.00

Explanation:

The family purchases 4 tickets. Each tickets cost x dollars with a purchase fee of $1.50. So we need to multiply 4 times the sum of x plus $1.50. The total cost of the tickets needs to be $38.00.

8 0
4 years ago
Calculate mean: 18, 24, 17, 21, 24, 16, 29, 18
aksik [14]

Answer:

20.875

Step-by-step explanation:

18+24+17+21+24+16+29+18=167/8=20.875

5 0
3 years ago
Read 2 more answers
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by
11111nata11111 [884]

Answer:

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is V=l\times b\times h

V=(11-2x)\times (7-2x)\times x

V=4x^3-36x^2+77x

Derivate w.r.t x,

V'(x)=4(3x^2)-2(36x)+77

V'(x)=12x^2-72x+77

The critical point when V'(x)=0

12x^2-72x+77=0

Solve by quadratic formula,

x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}

x=4.607,1.392

Derivate again w.r.t x,

V''(x)=24x-72

Now, V''(4.607)=24(4.607)-72=38.568>0 (+ve)

V''(1.392)=24(1.392)-72=-38.592 (-ve)

So, there is maximum at x=1.392.

The length of the box is l=11-2x

l=11-2(1.392)=8.216

The breadth of the box is b=7-2x

b=7-2(1.392)=4.216

The height of the box is h=1.392.

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is V=l\times b\times h

V=8.216\times 4.216\times 1.392

V=48.217\ in.^3

The volume of the box is 8.217 cubic inches.

5 0
3 years ago
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