7. Richard deposited $5400 and got back an amount of $6000 after 2 years.

Plz help i will mark brainliest :)))!

Rainbow [258]

Answer:

40 degree

180-57-40= 40

6 0

2 years ago

In a 45 45 90 right triangle the length of the hypotenuse is 15/2 what is length on one of the legs

Nikitich [7]

Hi there!

For any 45 45 90 right triangle, the length of the hypotenuse is always the square root of 2 times one of the legs.

To get the lengths of the leg, let's divide the length of the hypotenuse by the square root of 2.

We get the following:

$\frac{15}{ 2 \sqrt{2} }$

When simplifying fractions like this, we want to avoid having radicals on the bottom. In order to remove the radical from the denominator, let's multiply the numerator and the denominator by the square root of 2.

We get the following:

$\frac{15 \sqrt{2} }{4}$

That's your answer.

Have an awesome day! :)

- collinjun0827, Junior Moderator

8 0

2 years ago

Need help asap !!!!!

Romashka [77]

Answer:

The answer is x = 5.

Step-by-step explanation:

Given:

Δ ABC is an Isosceles triangle with AB = CA

m∠ ABC = ( 6x + 4 )°

m∠ BAC = 73°

m∠ BCA = ( 8y - 7 )°

To Find:

x = ?

Solution:

Properties of an Isosceles Triangle.

Base angles or two angles are equal.
Any two sides are equal.

Here , Δ ABC is an Isosceles triangle with AB = CA

∴ m∠ BAC = m∠ BCA

$73= 8y-7\\8y=73+7\\8y=80\\y=\frac{80}{10} \\y=10$

∴ m∠ BCA = ( 8y - 7 )°

= 8 × 10 - 7

m∠ BCA = 73 Which is same as ∠ CAB

Property of a Triangle is Sum of the measures of the angle of a triangle is 180°.

$\angle ACB + \angle CAB + \angle CBA = 180$

Substituting the values we get,

$73 + 73 + (6x+4) = 180\\6x+4=180-146\\6x=34-4\\6x=30\\x=\frac{30}{6} \\x=5\\$

The answer is x = 5.

7 0

3 years ago

How many times does 15 go into 128

Semenov [28]

The answer is: 8.533333 repeating or the fraction 128/5

If you divide 128/5, you will get that answer.

6 0

2 years ago

Read 2 more answers

John, sally, Natalie would all like to save some money. John decides that it would be best to save money in a jar in his closet

stiv31 [10]

Answer:

Part 1) John’s situation is modeled by a linear equation (see the explanation)

Part 2) $y=100x+300$

Part 3) $\$12,300$

Part 4) $\$2,700$

Part 5) Is a exponential growth function

Part 6) $A=6,000(1.07)^{t}$

Part 7) $\$11,802.91$

Part 8) $\$6,869.40$

Part 9) Is a exponential growth function

Part 10) $A=5,000(e)^{0.10t}$ or $A=5,000(1.1052)^{t}$

Part 11) $\$13,591.41$

Part 12) $\$6,107.01$

Part 13) Natalie has the most money after 10 years

Part 14) Sally has the most money after 2 years

Step-by-step explanation:

Part 1) What type of equation models John’s situation?

Let

y ----> the total money saved in a jar

x ---> the time in months

The linear equation in slope intercept form

$y=mx+b$

The slope is equal to

$m=\$100\ per\ month$

The y-intercept or initial value is

$b=\$300$

so

$y=100x+300$

therefore

John’s situation is modeled by a linear equation

Part 2) Write the model equation for John’s situation

see part 1)

$y=100x+300$

Part 3) How much money will John have after 10 years?

Remember that

1 year is equal to 12 months

so

$10\ years=10(12)=120 months$

For x=120 months

substitute in the linear equation

$y=100(120)+300=\$12,300$

Part 4) How much money will John have after 2 years?

Remember that

1 year is equal to 12 months

so

$2\ years=2(12)=24\ months$

For x=24 months

substitute in the linear equation

$y=100(24)+300=\$2,700$

Part 5) What type of exponential model is Sally’s situation?

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$P=\$6,000\\ r=7\%=0.07\\n=1$

substitute in the formula above

$A=6,000(1+\frac{0.07}{1})^{1*t}\\ A=6,000(1.07)^{t}$

therefore

Is a exponential growth function

Part 6) Write the model equation for Sally’s situation

$A=6,000(1.07)^{t}$

see the Part 5)

Part 7) How much money will Sally have after 10 years?

For t=10 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^{10}=\$11,802.91$

Part 8) How much money will Sally have after 2 years?

For t=2 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^{2}=\$6,869.40$

Part 9) What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$P=\$5,000\\r=10\%=0.10$

substitute in the formula above

$A=5,000(e)^{0.10t}$

Applying property of exponents

$A=5,000(1.1052)^{t}$

therefore

Is a exponential growth function

Part 10) Write the model equation for Natalie’s situation

$A=5,000(e)^{0.10t}$ or $A=5,000(1.1052)^{t}$

see Part 9)

Part 11) How much money will Natalie have after 10 years?

For t=10 years

substitute

$A=5,000(e)^{0.10*10}=\$13,591.41$

Part 12) How much money will Natalie have after 2 years?

For t=2 years

substitute

$A=5,000(e)^{0.10*2}=\$6,107.01$

Part 13) Who will have the most money after 10 years?

Compare the final investment after 10 years of John, Sally, and Natalie

Natalie has the most money after 10 years

Part 14) Who will have the most money after 2 years?

Compare the final investment after 2 years of John, Sally, and Natalie

Sally has the most money after 2 years

3 0

3 years ago

Read 2 more answers