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vova2212 [387]
3 years ago
15

Todos los átomos de un mismo elemento químico tienen el mismo número de neutrones verdad o mentira​

Chemistry
2 answers:
Pani-rosa [81]3 years ago
8 0

Answer:

all atoms of the same chemical element have the same number of neutrons true or false ANSWER NO

Explanation:

JulsSmile [24]3 years ago
6 0

verdad Todos los átomos de un elemento químico tienen el mismo número de protones, pero pueden diferenciarse en el número de neutrones. Se llaman Isótopos los átomos que tienen el mismo número de protones y se diferencian en el número de neutrones.

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How many liters are in 5.42 mols of O2 gas?<br><br> (2 decimal places)
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Explanation:

1 mol = 22.4 l

5.42 mol = 22.4 × 5.42 = 121.408

in two decimal place it is 121.41

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Which description best characterizes the motion of particles in a solid?
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The particles in a solid are tightly packed and locked in place. Although we cannot see it or feel it, the particles are vibrating in place.

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Read 2 more answers
The powder mixture (Cu, Al and Fe) = 10g was oxidized from sufficient chloride acid. 1) What are the possible reactions to the p
Mandarinka [93]

Answer:

1) 2Al + 6HCl ⟶ 2AlCl₃ + 3H₂

    Fe + 2HCl ⟶ FeCl₂ + H₂

2) Cu = 2.5 g; Al = 3.5 g; Fe = 4.0 g  

Explanation:

1) Possible reactions

2Al + 6HCl ⟶ 2AlCl₃ + 3H₂

Fe + 2HCl ⟶ FeCl₂ + H₂

2) Mass of each metal

a) Mass of Cu

The waste was the unreacted copper.

Mass of Cu = 2.5 g

b) Masses of Al and Fe

We have two relations :

Mass of Al + mass of Fe = 10 g - 2.5 g = 7.5 g

H₂ from Al + H₂ from Fe = 6.38 L at NTP

i) Calculate the moles of H₂

NTP is 20 °C and 1 atm.

\begin{array}{rcl}pV & = & n RT\\\text{1 atm} \times \text{6.38 L} & = & n \times 0.08206 \text{ L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{293.15 K}\\6.38 & = & 24.06n \text{ mol}^{-1} \\n & = & \dfrac{6.38}{24.06 \text{ mol}^{-1} }\\\\ & = & \text{0.2652 mol}\\\end{array}

(ii) Solve the relationship

 Let x = mass of Al. Then

7.5 - x = mass of Fe

Moles of Al = x/27

Moles of Fe = (7.5 - x)/56

Moles of H₂ from Al = (3/2) × Moles of Al = (3/2) × (x/27) = x /18

Moles of H₂ from Fe = (1/1) × Moles of Fe = (7.5 - x)/56

∴ x/18 + (7.5 - x)/56 = 0.2652

    56x + 18(7.5 - x) = 267.3

      56x + 135 - 18x = 267.3

                        38x = 132.3

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The masses of the metals are Cu = 2.5 g; Al = 3.5 g; Fe = 4.0 g

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