Answer:
3,78 mL of 12,0wt% H₂SO₄
Explanation:
The equilibrium in water is:
H₂O (l) ⇄ H⁺ (aq) + OH⁻ (aq)
The initial concentration of [H⁺] is 10⁻⁸ M and final desired concentration is [H⁺] = 
Thus, you need to add:
[H⁺] = 
= <em>5,31x10⁻⁸ M</em>
The total volume of the pool is:
7,00 m × 18,0 m ×1,50 m = 189 m³ ≡ 189000 L
Thus, moles of H⁺ you need to add are:
5,31x10⁻⁸ M × 189000 L = 1,00<em>x10⁻² moles of H⁺</em>
These moles comes from
H₂SO₄ → 2H⁺ +SO₄²⁻
Thus:
1,00x10⁻² moles of H⁺ × 
= <em>5,00x10⁻³ moles of H₂SO₄</em>
These moles comes from:
5,00x10⁻³ moles of H₂SO₄ × 
× 
× 
= <em>3,78 mL of 12,0wt% H₂SO₄</em>
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I hope it helps!
Answer:
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What is Metallic bond ?
- Metallic bond is a force that holds atoms together in a metallic substance.
Answer:
The number of moles of HCl in the 250 mL volumetric flask is 0.003 moles
Explanation:
Firstly, we solve for the concentration of acid using the formula
CaVa/CbVb = nₐ/nb
where Ca is the concentration of acid
Cb is the concentration of base
Va is the volume of acid
Vb is the volume of base
nₐ is the number of moles of acid (from the equation)
nb is the number of moles of base (from the equation)
Ca × 250/0.09876 × 29.59 = 1/1
Ca = 0.09876 × 29.59/250
Ca = 0.012 M
To determine the number of moles of HCl acid present in the 250 ml volumetric flask, the formula for molarity is used
Molarity = number of moles ÷ volume (in liter or dm³)
Volume needs to be converted to liter; 250 ml ⇒ 0.25 L
Molarity of the acid is 0.012 M
From the formula above, number of moles = molarity × volume (in liter)
number of moles = 0.012 × 0.25
number of moles of acid = 0.003 moles
