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3 years ago

Which example shows a double replacement reaction?

Chemistry

1 answer:

Vikki [24]3 years ago

4 0

Answer:

KCl + AgNO₃ —> AgCl + KNO₃

Explanation:

To answer the question correctly, we must understand the definition of a double displacement reaction.

A double displacement reaction is a reaction in which the ions of the two reacting compounds exchange to form new compounds different from the two reacting compounds. Example is given below:

XY + AB —> XB + AY

Considering the options given in the question above, only the equation:

KCl + AgNO₃ —> AgCl + KNO₃

Satisfy the definition of a double displacement reaction.

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What parts of the earth include hydrosphere

Natasha2012 [34]

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Explanation:

6 0

3 years ago

Explain what would happen if an electron and a proton were brought near each other and then released. why would this happen?

Leni [432]

They would repel one another because they they have opposing charges

3 0

4 years ago

If you combine 27.1 g of a solute that has a molar mass of 27.1 g/mol with 100.0 g of a solvent, what is the molality of the res

baherus [9]

<u>Answer:</u> The molality of the solution is 0.1 m.

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

$Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

Where,

$m_{solute}$ = Given mass of solute = 27.1 g

$M_{solute}$ = Molar mass of solute = 27.1 g/mol

$W_{solvent}$ = Mass of solvent = 100 g

Putting values in above equation, we get:

$\text{Molality of solution}=\frac{27.1\times 1000}{27.1\times 100}\\\\\text{Molality of solution}=0.1m$

Hence, the molality of the solution is 0.1 m.

8 0

3 years ago

Read 2 more answers

As a cooking method, braising is valued for its A. ability to retain flavor. B. quickness and convenience. C. simplicity and ver

LiRa [457]

Answer:

i belevie its A

Explanation:

took the test

7 0

3 years ago

Use the following half-reactions to write three spontaneous reactions, calculate E°cell for each reaction, and rank the oxidizin

Ainat [17]

Answer:

See explaination

Explanation:

we know that

half cell with higher reduction potential is cathode

cathode :

N20 + 2H+ + 2e- ---> N2 + H20

anode :

Cr(s) ---> Cr+3 + 3e-

overall reaction is

3 N20 + 6H+ + 2 Cr ---> 3N2 + 3H20 + 2Cr+3

now

Eo cell = Eo cathode - Eo anode

EO cell = 1.77 + 0.74

Eo cell = 2.51 V

now

in this case

oxidizing agents are N20 and Cr+3

reducing agents are Cr and N2

higher the reduction potential , stronger the oxidizing agent

lower the reduction potential , stronger the reducing agent

oxidzing agents

N20 > Cr+3

reducing agents

Cr > N2

cathode :

Au+ + e- --> Au

anode :

Cr ---> Cr+3 + 3e-

overall reaction

3Au+ + Cr ---> 3Au + Cr+3

Eo cell = 1.69 + 0.74

Eo cell = 2.43

now

oxidizing agents :

Au+ > Cr+3

reducing agents :

Cr > Au

cathode :

N20 + 2H+ + 2e- ---> N2 + H20

andoe :

Au ---> Au+ + e-

overall

2 Au + N20 + 2H+ --> 2 Au+ + N2 + H20

Eo cell = 1.77 - 1.69

Eo cell = 0.08

oxidizing agents

N20 > Au+

reducing agents

Au > N2

8 0

3 years ago