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anyanavicka [17]
3 years ago
14

8. Benzene is an aromatic hydrocarbon with molecular formula C6H6. a) Draw the ring structure of Benzene. [1] how will you prepa

re benzene from phenol​
Chemistry
1 answer:
kvv77 [185]3 years ago
3 0

When phenol is heated with zinc dust benzene is obtained.

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Which of the mole ratios would be used to set up the below problem?
san4es73 [151]
A.3 moles H2

1 mole N2

I think it is correct
4 0
3 years ago
Acetone major species present when dissolved in water
jek_recluse [69]

Answer: acetone molecule ( CH₃-CO-CH₃)


Explanation:


1) Acetone is CH₃-CO-CH₃


2) That is a molecule (build up of covalent bonds).


3) When dissolved, covalent bonded compounds remain as separate molecules, then it is said that the major species present in the solution is the molecule. The molecules of acetone are surrounded (sovated) by the molecules of water.


This as opposed to the case of ionic compounds that ionize. When a compound as NaCl dissolves in water, it ionizes completely, so the major speceies are not NaCl formulas, but the ions Na⁺ and Cl⁻, not molecules.


That leads to the answer: the major species present when acetone is dissolved in water is the molecules of acetone (you do not need to state the fact that the molecules of water are part of the solution, because that is not the target of the question).



3 0
3 years ago
What compound are formed with lithium and selenium?
love history [14]

Answer:

Lithium selenide Lithium selenide (Li2Se) 12136-60-6 Dilithium selenide lithium selenidolithium

Molecular Weight 92.9 g/mol

Dates Modify 2020-11-15 Create 2005-08-08

5 0
3 years ago
Read 2 more answers
Use kinetic molecular theory to explain why a gas takes the shape and volume of its container
Tamiku [17]

Answer:

Imo : Gas particles are in constant, random motion. The volume of gas particles is negligible in comparison to the volume of the container. There are no attractive forces between gas particles.

7 0
3 years ago
Determine the [h3o+] of a 0.210 m solution of formic acid.
Nataly [62]
When the Pka for formic acid = 3.77
and Pka = -㏒ Ka 
   3.77 = -㏒ Ka
∴Ka = 1.7x10^-4 

when Ka = [H+][HCOO-}/[HCOOH]

when we have Ka = 1.7x10^-4 &[HCOOH] = 0.21 m
so by substitution: by using ICE table value
1.7x10^-4 = X*X / (0.21-X)
(1.7x10^-4)*(0.21-X) = X^2      by solving this equation for X

∴X = 0.0059
∴[H+] = 0.0059
∴PH= -㏒ [H+]
       = -㏒ 0.0059
       = 2.23 

3 0
3 years ago
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