<span>The name of the shape graphed by the function r ^ 2 = 9
cos (2 theta) is called the “<u>lemniscate</u>”. A lemniscate is a
plane curve with a feature shape which consists of two loops that meet at a
central point. The curve is also sometimes called as the lemniscate of
Bernoulli. </span>
Explanation:
The
period of coskθ is 2π/k. In this case, k = 2 therefore the
period is π.
r ^ 2 = 9 cos 2θ ≥0 → cos 2θ ≥0. So easily
one period can be chosen as θ ∈
[0, π] wherein cos 2θ ≥0.
As cos(2(−θ)) = cos2θ, the graph is symmetrical about the initial line.
Also,
as cos (2(pi-theta) = cos 2theta, the graph is symmetrical about the
vertical θ = π/2
A
Table for half period [0,π4/] is
adequate for the shape in Quarter1
Use symmetry for the other three quarters:
(r, θ) : (0,3)(3/√√2,π/8)(3√2/2,π/6)(0,π/4<span>)</span>
Answer:
I think it is 84 hope this helps
Answer:
y = -2x + 2
General Formulas and Concepts
<u>Pre-Alg</u>
- Order of Operations: BPEMDAS
<u>Algebra I</u>
Slope-Intercept Form: y = mx + b
Slope Formula: 
Step-by-step explanation:
<u>Step 1: Define</u>
Point (-1, 4)
y-intercept (0, 2)
<u>Step 2: Find slope </u><em><u>m</u></em>
- Substitute:
- Subtract/Add:
- Divide:
<u>Step 3: Write linear equation</u>
y = -2x + 2
Assuming that the base of the prism is a regular pentagon, the area of a regular polygon is given by the formula A = 0.5pa; where p is the perimeter and a is the apothem. An apothem is a line that connects the center of the polygon to the midpoint of a side and is also perpendicular to the said side. For this example, the assumed apothem here is k.
Area of base = 2 (0.5 x 20" x k) = 20k
The sides of the prism are rectangles, with width 6" and length (20"/5) = 4".
Area of sides of prism = 5 (6" x 4") = 120
Total Area T.A. = 120 + 20k
4.112/15=7.466666...
the answer is 8.
5.the answer is 7.
6.2*6-9=3.
Merry Christmas <span />
