Answer:
51.8 L is the new volume
Explanation:
In the two situations we have this relationship:
P ₁ . V₁ / T₁ = P₂ . V₂ / T₂
Let's convert the temperature to absolute values
T°K = T°C + 273
22.9°C + 273 = 295.9 K
44.5°C + 273 = 317.5 K
Let's convert now, the Torr to atm.
778 Torr . 1 atm / 760 Torr = 1.02 atm
Now we can replace:
3.4 atm . 14.5L / 295.9K = 1.02 atm . V₂ / 317K
(3.4 atm . 14.5L / 295.9K) . 317 K = 1.02 atm . V₂
( (3.4 atm . 14.5L / 295.9K) . 317 K ) / 1.02 atm = V₂ → 51.8 L
P ₁ . V₁ / T₁ = P₂ . V₂ / T₂ is derived from the Ideal Gases Law equation, and it is fulfilled when the moles of a gas, remains constant after the change of T°, pressure and volume.
They are the sugars, starches, and fibers that’s found in fruits, vegetables, grains, and milk products.
Answer:
Add excess copper carbonate to hydrochloric acid in a beaker, stirring until there is no further reaction. Filter the mixture to remove the remaining copper carbonate, then heat the remaining solution to the point of crystallisation. Leave the solution to cool and collect the crystals formed by filtration.
Explanation:
Answer:
The correct option is;
It is used during photosynthesis to capture sunlight
Explanation:
During photosynthesis, light energy from the Sun is converted and stored in sugars as chemical energy. The Sun light energy is used in the formation of complex sugars such as glucose from the combination of water from the ground and carbon dioxide from the atmosphere while oxygen is released as the byproduct. Organisms are then able to obtain energy from the glucose as well as carbon fiber
The chemical equation for the reaction is as follows;
6CO₂ + 12H₂O + light energy → C₂H₁₂O₆ + 6O₂ + 6H₂O
Carbon, Water, GLucose, Oxygen, Water
dioxide
The reaction between oxygen, O2, and hydrogen, H2, to produce water can be expressed as,
2H2 + O2 --> 2H2O
The masses of each of the reactants are calculated below.
2H2 = 4(1.01 g) = 4.04 g
O2 = 2(16 g) = 32 g
Given 1.22 grams of oxygen, we determine the mass of hydrogen needed.
(1.22 g O2)(4.04 g H2 / 32 g O2) = 0.154 g of O2
Since there are 1.05 grams of O2 then, the limiting reactant is 1.22 grams of oxygen.
<em>Answer: 1.22 g of oxygen</em>