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Rudik [331]
3 years ago
9

Which has the most gravitational potential energy- a 10 kg ball that is 2 meters high or a 10 kg ball that is 4 meters high?

Chemistry
1 answer:
Alenkasestr [34]3 years ago
3 0

Answer:

The 10 kg ball that is 4 meters high is greater than a 10 kg ball that is 2 meters high

Explanation:

From the question,

Gravitational Potential Energy of the first ball

P.E1 = mgh.................... Equation 1

Where P.E1 = Gravitational Potential Energy of the first ball, m = mass of the first ball, h = height of the first ball, g = acceleration due to gravity.

Given: m = 10 kg, h = 2 m

Constant: g = 9.8 m/s²

Substitute these values into equation 1

P.E1 = 10×2×9.8

P.E1 = 196 J.

Similarly,

Gravitational potential energy of the second ball is

P.E2 = m'gh'................... Equation 2

Where P.E2 = Gravitational potential Energy of the second ball, m' = mass of the second ball, h' = height of the second ball.

Given; m' = 10 kg, h' = 4 m

Substitute these values into equation 2

P.E2 = 10×4×9.8

P.E2 = 392 J

From the above calculation,

P.E2 is greater than P.E1.

Hence, the 10 kg ball that is 4 meters high is greater than a 10 kg ball that is 2 meters high

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8 0
3 years ago
0.500 L of a gas is collected at 2911 MM and 0°C. What will the volume be at STP?
ioda

Answer:

V₂ =  1.92 L

Explanation:

Given data:

Initial volume = 0.500 L

Initial pressure =2911 mmHg (2911/760 = 3.83 atm)

Initial temperature = 0 °C (0 +273 = 273 K)

Final temperature = 273 K

Final volume = ?

Final pressure = 1 atm

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

by putting values,

V₂ = P₁V₁ T₂/ T₁ P₂  

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