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gayaneshka [121]
3 years ago
12

A student creates a ball-and-stick model to represent the atomic scale of a substance. Which of the following best describes the

model?
A. 1 molecule with 10 atoms
B. 1 element with 10 molecules
C. 10 molecules representing 10 elements
D. 10 elements representing 10 molecules

Chemistry
2 answers:
laila [671]3 years ago
5 0
Answer is: <span>A. 1 molecule with 10 atoms.
Every ball represent one atom in one molecule.
</span><span>The </span>ball and stick model<span> is a </span>molecular model<span> of a </span>chemical substance<span> that shows the </span>three-dimensional<span> position of the </span>atoms<span> and the </span>bonds between them. <span>The atoms have spherical shape and they are </span><span>connected with sticks (one, two or three, depends on bonds).</span>
vichka [17]3 years ago
3 0

Answer:

Option A. 1 molecule with 10 atoms

Explanation:

Each ball in the diagram represents an atom and the stick represents a bond.

A careful look at the diagram of the student's model reveals that the student's model contains 10 balls which represents 10 atoms. This means that a molecule of the student ball-and-stick model contains 10 atoms.

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Explanation:

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3 years ago
Plz help
suter [353]

Answer:

Explanation:

There's a great many assumptions in this question. We have to assume  that the rod was completely immersed. We also have to note that we can read the volumes to 3 places accurately. School graduated cylinders are not that accurate.

Leaving those objections aside,  here is how the question should be done.

Final volume = 15.0 mL

Initial volume = 10.0 mL

Water displaced = 5.0 mL

The amount of water displaced is the same as the volume of the metal rod.

Finally the mass of the rod is 12.0 grams.

Density = mass / volume

Density = 12.0 grams / 5.0 mL

density= 2.4 grams / mL   a mL and a cc^3 are the same thing.

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3 0
3 years ago
How many grams of carbon dioxide are created from the complete combustion of 21.3 L of butane at STP?
Bond [772]

Answer:

165.5 g of CO2

Explanation:

We must first put down the balanced reaction equation:

C4H10(g) + 13/2 O2(g) ------> 4CO2(g) + 5H2O(g)

From the reaction equation, one mole of butane occupies 22.4 L hence we can establish the stoichiometry of the reaction thus:

22.4 L of butane created 174 g of CO2

Therefore 21.3 L of butane will create 21.3 × 174/22.4 = 165.5 g of CO2

3 0
4 years ago
Pb (NO3)2 (aq)+KCl (aq) Express answer as a chemical equation enter if reaction if no reaction occurs identify all phases
enot [183]

Answer:

Pb (NO₃)₂(aq) + 2KCl(aq)     →   2KNO₃(aq)    +  PbCl₂(s)

Explanation:

In given chemical equation the aqueous lead (II) nitrate react with aqueous potassium chloride and form aqueous potassium nitrate and lead chloride.

Chemical equation:

Pb (NO₃)₂(aq) + KCl(aq)     →   KNO₃(aq)    +  PbCl₂(s)

Balanced chemical equation:

Pb (NO₃)₂(aq) + 2KCl(aq)     →   2KNO₃(aq)    +  PbCl₂(s)

ionic equation:

Pb²⁺ (aq) + 2NO₃⁻ (aq) + 2K⁺(aq)  +  2Cl⁻ (aq)    →     2NO₃⁻(aq)  + 2K⁺(aq)  +  PbCl₂(s)

Net ionic equation:

Pb²⁺ (aq) +  2Cl⁻ (aq)    →   PbCl₂(s)

The NO₃⁻(aq) and  K⁺(aq) are spectator ions that's why these are not written in net ionic equation. The PbCl₂ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

8 0
3 years ago
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