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Mariana [72]
3 years ago
6

Point E is located at coordinates (-7,-5). Point F is located at coordinated (-2,7) what is length EF

Mathematics
2 answers:
sweet-ann [11.9K]3 years ago
6 0

Answer:

13 units.

The answer above is correct!

Step-by-step explanation:

Stella [2.4K]3 years ago
3 0

Answer:

EF = 13 units

Step-by-step explanation:

Points E and F are the ends of segment EF.

Coordinates of E → (-7, -5)

Coordinates of F → (-2, 7)

Since, length of a segment joining points (x_1,y_1) and (x_2,y_2) is given by,

Length of segment = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

Length of segment EF = \sqrt{(-7+2)^2+(-5-7)^2}

                                     = \sqrt{(-5)^2+(-12)^2}

                                     = \sqrt{169}

                                     = 13

Therefore, length of segment EF is 13 units.

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