Answer:
element A has a mass of 2 units, while an atom of element B
has a mass of 5 units, what would be the mass of the
compound A3 B2
Explanation:
T<span>he balanced reaction is as follows;
Ca(OH)</span>₂<span> + 2HCl ---> CaCl</span>₂<span> + 2H</span>₂<span>O
stoichiometry of Ca(OH)</span>₂<span> to HCl is 1:2
number of moles of Ca(OH)</span>₂<span> reacted = 0.120 mol/L x 0.0240 L = 0.00288 mol according to molar ratio of 1:2 number of HCl moles reacted = twice the number of Ca(OH)</span>₂<span> moles reacted
number of HCl moles reacted = 0.00288 mol x 2 = 0.00576 mol
number of HCl moles in 160 mL - 0.00576 mol
therefore number of HCl moles in 1000 mL - 0.00576 mol / 160 mL x 1000 mL = 0.036 mol
molarity of HCl = 0.036 M</span>
<span>K D = 1.0g/ 28 ml 0.0357
-------------- = ---------- = 1.65
1.0 g/46 ml 0.0217
is the distribution coefficient of caffeine in this solvent system</span>
There are approximately 6.02 × 10²³ atoms of phosphorus in one mole of 30.974 grams of phosphorus (option A).
<h3>How to calculate number of atoms?</h3>
The number of atoms of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number. That is;
no of atoms = no of moles × 6.02 × 10²³
According to this question, there are 30.974 grams of phosphorus in one mole of phosphorus. The number of atoms can be calculated as follows:
no of moles of P = 30.974g ÷ 31g/mol = 0.99mol
number of atoms = 0.99 mol × 6.02 × 10²³
number of atoms = 6.02 × 10²³ atoms
Therefore, there are approximately 6.02 × 10²³ atoms of phosphorus in one mole of 30.974 grams of phosphorus.
Learn more about number of atoms at: brainly.com/question/8834373
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