In zero order reactions the rate of reaction is independent of reactant concentrations. That is the rate of the reaction does not vary with increasing nor decreasing reactants concentrations. On the other hand, first order reaction are reactions in which the rate of reaction is directly proportional to the concentration of the reacting substance (reactants). In this case, i believe the rate of reaction will triple( increase by a factor of 3)
B: 210.8 rounded to 210 is totally wrong, and the reason why is because 210.8 rounded to the nearest whole number is 211, not 210. So B is the one with the error (this option is correct) and the other user that said D, is wrong since 18.42 does round to 18.4.
Hope this helped!
Nate
The acceleration at the bottom of the loop is 34m/
Explanation:
<u>Given: </u>
Mass=52kg
Force=1750N
To calculate:
The acceleration at the bottom of the loop
<u>Formula:
</u>
Force=Mass x Acceleration
1750=52 x Acceleration
1750/52=Acceleration
Therefore acceleration at the bottom of the loop is 34m/
Roller coasters are mainly based upon acceleration theory they have two types of acceleration one is at the top of the loop and the other is at the bottom of the loop.
Then the net forces and the values are given. In many problems the roller coaster concept is included and it gives another level of clarity to the problems including the net forces
Answer:
Explanation:
For this interesting problem, we use the definition of centripetal acceleration
a = v² / r
angular and linear velocity are related
v = w r
we substitute
a = w² r
the rectangular body rotates at an angular velocity w
We locate the points, unfortunately the diagram is not shown. In this case we have the axis of rotation in a corner, called O, in one of the adjacent corners we call it A and the opposite corner A
the distance OB = L₂
the distance AB = L₁
the sides of the rectangle
It is indicated that the acceleration in in A and B are related
we substitute the value of the acceleration
w² r_A = n r_B
the distance from the each corner is
r_B = L₂
r_A =
we substitute
\sqrt{L_1^2 + L_2^2} = n L₂
L₁² + L₂² = n² L₂²
L₁² = (n²-1) L₂²