C.
It is a motion with uniform acceleration, meaning that the acceleration will not change.
The object is thrown upwards with a positive velocity. This shows that the upward direction is positive. The object will decelerate due to gravity at a magnitude of 9.81 m/s2. Therefore, the acceleration is -9.81 m/s2.
Note that even though the velocity of the object is momentarily 0 m/s at maximum height, there is still a constant acceleration.
This allows the object first decelerate upwards, then change direction at max height, and finally accelerate downwards. So in this case, the acceleration is always negative and unchanged.
Aster's final position from her initial position is 63 m approximately. She will head north west direction to return to her initial position
<h3>
What is Displacement ?</h3>
Displacement is the distance travelled in a specific direction. It is a vector quantity.
Given that a person walks first 70 m in the direction 37° north of east, and then walks 82 m in the direction 20° south of east, and finally walks 28 m in the direction 30° west of north.
a) Let P be the Aster's final position from her initial position?
We can use bearing by using Cosine formula to solve this question.
P² = 70² + 82² - 2 × 70 × 82 cos 73
P² = 4900 + 6724 - 11480 cos 73
P² = 11624 - 3356.43
P² = 8267.57
P = √8267.57
P = 90.9 m
P = 90.9 - 28
P = 62.9 m
We can get the angle by using Sine rule
82/ sin Ф = 90.9 / sin 73
sin Ф = 0.8627
Ф =
(0.8627)
Ф = 59.6°
Ф = 60°
b) She will head north west direction to return to her initial position
Learn more about Displacement here: brainly.com/question/2109763
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Boyle's law is modeled by the equation p1v1=p2v2.
Given:
An ideal gas expands at constant pressure:
P = 105 pascals
V1 = 1 m3
V2 = 4 m3
then, the gas is compressed to 1/3 of the pressure and volume 2.50 m3.
Work at constant pressure:
W = PΔV
W = 105 pascals * (4 m3 - 1 m3)
W = 315 Joules
Work at constant volume is zero.
The volume of water displaced in the beaker is equal to the volume of the submerged part of the can.