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ELEN [110]
3 years ago
10

que 2. Why do we keep frequency constant instead of keeping vibrating length constam second law of vibrating string?​

Physics
1 answer:
ella [17]3 years ago
8 0

Answer:

The second law of a vibrating string states that for a transverse vibration in a stretched string, the frequency is directly proportional to the square root of the string's tension, when the vibrating string's mass per unit length and the vibrating length are kept constant

The law can be expressed mathematically as follows;

f = \dfrac{1}{2\cdot l} \cdot \sqrt{\dfrac{T}{m} }

The second law of the vibrating string can be verified directly, however, the third law of the vibrating string states that frequency is inversely proportional to the square root of the mass per unit length cannot be directly verified due to the lack of continuous variation in both the frequency, 'f', and the mass, 'm', simultaneously

Therefore, the law is verified indirectly, by rearranging the above equation as follows;

m = \dfrac{1}{ l^2} \cdot \dfrac{T}{4\cdot f^2} }

From which it can be shown that the following relation holds with the limits of error in the experiment

m₁·l₁² = m₂·l₂² = m₃·l₃² = m₄·l₄² = m₅·l₅²

Explanation:

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A solenoid that is 78.8 cm long has a cross-sectional area of 15.9 cm2. There are 914 turns of wire carrying a current of 8.25 A
Harlamova29_29 [7]

Answer:

(a) Energy density will be equal to 57.31J/m^3

(b) Total energy will be equal to 0.0718 J

Explanation:

It is given that length of solenoid l = 78.8 cm = 0.788 m

Cross sectional area A=15.9cm^2=15.9\times 10^{-4}m^2

Number of turns of the wire N = 914

Current in the solenoid i = 8.25 A

Inductance of the wire is equal to L=\frac{\mu _0N^2A}{l}=\frac{4\pi \times 10^{-7}\times 914^2\times 15.9\times 10^{-4}}{0.788}=2.117\times 10^{-3}H

(b) Total energy stored in magnetic field U=\frac{1}{2}Li^2=\frac{1}{2}\times 2.11\times 10^{-3}\times 8.25^2=0.0718J

(a) Energy density will be equal to

U_b=\frac{0.0718}{15.9\times 10^{-4}\times 0.788}=57.31J/m^3

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