Answer:
v = 7.67 m/s
Explanation:
Given data:
horizontal distance 11.98 m
Acceleration due to gravity 9.8 m/s^2
Assuming initial velocity is zero
we know that

solving for t
we have

substituing all value for time t

t = 1.56 s
we know that speed is given as


v = 7.67 m/s
Answer:
489.19m
Explanation:
To find the minimum distance you first calculate the time in which the teacher stops:

however, the reaction of the teacher is 0.31s later, then you use
t=13.8-0.31s=13.49s
during this time the camper has traveled a distance of:
(1)
Next you calculate the distance that teacher has traveled for 13.6s:
(2)
The minimum distance between the driver and the camper will be the difference between (2) and (1):

Answer:
A.) V = 14 m/s
B.) h = 36.6 m
Explanation:
Given the formula v = √2gh
where g = 9.8m/sec^2 is the acceleration due to gravity.
A.) Determine the impact velocity for an object dropped from a height of 10 m.
Substitute height h in the given formula
V = √2gh
V = √2 × 9.8 × 10
V = √196
V = 14 m/s
b. Determine the height required for an object to have an impact velocity of 26.8 m/sec (~ 60 mph). Round to the nearest tenth of a meter.
Substitute the velocity in the given formula and make height h the subject of formula.
26.8 = √2 × 9.8 × h
Square both sides
718.24 = 19.6h
h = 718.24 / 19.6
h = 36.64 m
h = 36.6 m
Answer:
d) 3 m/s
Explanation:
As we know by equation of continuity

here we have



now from above equation we have


here we have

