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Alex Ar [27]
2 years ago
12

The volume of this cylinder is 1751 cubic units. What is the volume of a cone that has the same base area and the sam height

Mathematics
1 answer:
siniylev [52]2 years ago
6 0

Answer:

V_2 = 583.67

Step-by-step explanation:

Given

Represent the volume of the cylinder with V1 and the cone with V2.

So:

V_1 = 1751

Required

Find V2

The volume of a cylinder is:

V_1 = \pi r^2h

Because the cone and the cylinder have the same base area and height, the volume of the cone is:

V_2 = \frac{1}{3}\pi r^2h

Substitute V_1 for \pi r^2h.

V_2 = \frac{1}{3}\pi r^2h

V_2 = \frac{1}{3}V_1

Substitute 1751 for V1

V_2 = \frac{1}{3} * 1751

V_2 = \frac{1* 1751}{3}

V_2 = \frac{1751}{3}

V_2 = 583.67

<em>The volume of the cone is 583.67 cubic units</em>

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LekaFEV [45]

Answer: y-1=\dfrac32(x+3)

Step-by-step explanation:

Slope of a line passes through (a,b) and (c,d) = \dfrac{d-b}{c-a}

In graph(below) given line is passing through (-2,-4) and (2,2) .

Slope of the given line passing through (-2,-4) and (2,2) =\dfrac{-4-2}{-2-2}=\dfrac{-6}{-4}=\dfrac{3}{2}

Since parallel lines have equal slope . That means slope of the required line would be .

Equation of a line passing through (a,b) and has slope m is given by :_

(y-b)=m(x-a)

Then, Equation of a line passing through(-3, 1) and has slope =  is given by

(y-1)=\dfrac32(x-(-3))\\\\\Rightarrow\ y-1=\dfrac32(x+3)

Required equation: y-1=\dfrac32(x+3)

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2 years ago
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erastova [34]

Answer:

This should be parallel.

Step-by-step explanation:

Two lines are said to be parallel only if their slope matches. They are said to be perpendicular only if the slopes are negative reciprocals.

Here, you should put both equations in slope intercept form which is y=mx+b. The letter "M" represents the slope of both equations.

2y-6=3x+4 turns into 2y=3x+10 after adding 6 and into y=3/2x+5 after dividing the equation by 2. The slope for this equation is 3/2.

8y=12x+8 must be divided by 8 to be in slope intercept form. This equation becomes y=3/2x+1. Here the slope is also 3/2.

The slopes for each equation match making these lines parallel.

4 0
2 years ago
What is the discriminant of the quadratic equation?
Kipish [7]

Answer:

The discriminant is the part under the square root in the quadratic formula, b²-4ac. If it is more than 0, the equation has two real solutions. If it's less than 0, there are no solutions. If it's equal to 0, there is one solution.

Step-by-step explanation:

4 0
3 years ago
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stira [4]
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2 years ago
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the graph of y=e^tanx-2 crosses the x axis at one point in the interval [0,1]. What is the slope of the graph at this point? I g
Svetlanka [38]
Y = e^tanx   -   2

To find at which point it crosses x axis we state that y= 0

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to find slope at that point first we need to find first derivative of funtion y.

y' = (e^tanx)*1/cos^2(x)

now we express x = 0.6061 in y' and we get:
y' = k = 2,9599
3 0
2 years ago
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