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balu736 [363]
3 years ago
13

Do you know the answer toPart A: 25% of 50 = Part B: 25% of 60 = Part C: 50% of 60 = Part D: 75% of 60 = Part E: 75% of 30 = Par

t F: 100% of 22.5 = Part G: 10% of 22.5 = Part H: 50% of 45.7 =
Mathematics
1 answer:
Verdich [7]3 years ago
6 0

Answer:

Part A: 25% of 50 = 12.5

Part B: 25% of 60 = 15

Part C: 50% of 60 = 30

Part D: 75% of 60 = 45

Part E: 75% of 30 = 22.5

Part F: 100% of 22.5 = 22.5

Part G: 10% of 22.5 = 2.25

Part H: 50% of 45.7 = 22.85

Step-by-step explanation:

To find - Do you know the answer to

              Part A: 25% of 50 =

              Part B: 25% of 60 =

              Part C: 50% of 60 =

              Part D: 75% of 60 =

              Part E: 75% of 30 =

              Part F: 100% of 22.5 =

              Part G: 10% of 22.5 =

              Part H: 50% of 45.7 =

Proof -

Part A :

25% of 50 =  \frac{25}{100} *50 = \frac{1}{4}*50 = 12.5

⇒25% of 50 = 12.5

Part B :

25% of 60 =  \frac{25}{100} *60 = \frac{1}{4}*60 = 15

⇒25% of 60 = 15

Part C :

50% of 60 =  \frac{50}{100} *60 = \frac{1}{2}*60 = 30

⇒50% of 60 = 30

Part D :

75% of 60 = \frac{75}{100} *60 = \frac{75}{10}*6 = 45

⇒75% of 60 = 45

Part E :

75% of 30 = \frac{75}{100} *30 = \frac{75}{10}*3 = 22.5

⇒75% of 30 = 22.5

Part F :

100% of 22.5 = \frac{100}{100} *22.5 = 22.5

⇒ 100% of 22.5 = 22.5

Part G :

10% of 22.5 = \frac{10}{100} *22.5 = 2.25

⇒ 10% of 22.5 = 2.25

Part H :

50% of 45.7 =  \frac{50}{100} *45.7 = \frac{1}{2}*45.7 = 22.85

⇒50% of 45.7 = 22.85

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Answer:

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3 years ago
Help
ycow [4]

Answer:

hat: $12

t-shirt: $8

Step-by-step explanation:

Let the price of 1 hat = h.

Let the price of 1 t-shirt = t.

Julie: h + 2t = 28

Raj: 2h + t = 32

We have a system of 2 equations in 2 variables.

h + 2t = 28

2h + t = 32

Let's use the substitution method to solve the system of equations.

Solve the first equation for h.

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Substitute 28 - 2t for h in the second equation.

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3 years ago
Convert 1 cal/(m^2 * sec * °C) into BTU/(ft^2 * hr * °F)
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Answer:

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Step-by-step explanation:

To find : Convert 1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C} into \frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Solution :

We convert units one by one,

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1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

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