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3 years ago

Where are chemicals found?

Chemistry

2 answers:

ollegr [7]3 years ago

6 0

Answer: c

Explanation: pretty sure its c :]

Volgvan3 years ago

5 0

It’s going to be C solids, liquids, and gases

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3-ethyl-2-methyl-2-pentene

gayaneshka [121]

See photo for drawing :)

3 0

4 years ago

When 0.105 mol propane, C3H8 is burned in an excess of oxygen, how many moles of oxygen are consumed? The products are carbon di

torisob [31]

<u>Answer:</u> The amount of oxygen gas consumed is 0.525 moles

<u>Explanation:</u>

We are given:

Moles of propane burned = 0.150 moles

The chemical equation for the combustion of propane follows:

$C_3H_8+5O_2\rightarrow 3CO_2+4H_2O$

By Stoichiometry of the reaction:

1 mole of propane reacts with 5 moles of oxygen gas

So, 0.150 moles of propane will react with = $\frac{5}{1}\times 0.105=0.525mol$ of oxygen gas

Hence, the amount of oxygen gas consumed is 0.525 moles

6 0

3 years ago

A 10.0 mL sample of HNO3 was exactly neutralized by 13.5 mL of 1.0 M KOH. What is the molarity of the HNO3? Use the titrations f

Kruka [31]

Answer: Thus molarity of $HNO_3$ is 1.35 M

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HNO_3$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is KOH.

We are given:

$n_1=1\\M_1=?M\\V_1=10.0mL\\n_2=1\\M_2=1.0M\\V_2=13.5mL$

Putting values in above equation, we get:

$1\times M_1\times 10.0=1\times 1.0\times 13.5\\\\M_1=1.35M$

Thus molarity of $HNO_3$ is 1.35 M

7 0

3 years ago

Nitric Oxide gas react to form nitrogen dioxide as shown in the following reaction:

Zina [86]

Answer:

2 moles of NO2 would be produced.

Explanation:

Here, you will have to do a mole to mole ratio.

2 moles NO x (2 moles NO2 / 2 moles NO)

= 2 moles NO2

6 0

3 years ago

calculate the number of photons having a wavelength of 10 waves/s required to produce 1.0 kJ of energy

sp2606 [1]

4.5 kj energy thankkksss

6 0

3 years ago