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natta225 [31]
3 years ago
11

Predict whether a precipitation reaction will occur when aqueous solutions of pbcl2 and (nh4)2s

Chemistry
1 answer:
Nutka1998 [239]3 years ago
5 0
Answer : YES, The precipitation reaction will occur.

Explanation : When we mix the aqueous solutions of Lead chloride and Ammonium sulfide a reaction will occur which is stated below :

PbCl_{2} +(NH_{4}) _{2} S ----\ \textgreater \  PbS + 2[ (NH_{4})Cl]

The major product that is formed is Lead sulfate which is black in colour.

Once the reaction is complete one can observe a black precipitate getting obtained. 
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A runner travels at a constant speed of 4 m/s. What happens to the velocity of the runner when the runner changes direction?
ANTONII [103]

Answer:

4m/s in the direction of the turn

Explanation:

The velocity of an object is the rate of change of its position with respect to a frame of reference.

Assuming the runner stays the same speed as he turns, his velocity will be 4m/s in the speed he turns.

5 0
3 years ago
Write the nuclear equation for the beta decay<br> of calcium-45.
TiliK225 [7]

Answer:

on https://www.ck12.org/book/peoples-physics-concepts/section/20.1/

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3 years ago
Why is acid added to water during eletrolysis
DedPeter [7]

Answer:

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4 0
3 years ago
jamie is not sure a new medication will work because it has not had a large test group. Is jamie being creative?
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7 0
3 years ago
05. When a gold pebble is placed in a graduated cylinder that contains 12.0 mL of water, the water level rises
OLga [1]

Answer:

142.82 g

Explanation:

The following data were obtained from the question:

Volume of water = 12 mL

Volume of water + gold = 19.4 mL

Density of gol= 19.3 g/cm³

Mass of gold =.?

Next, we shall determine the volume of the gold. This can be obtained as follow:

Volume of water = 12 mL

Volume of water + gold = 19.4 mL

Volume of gold =.?

Volume of gold = (Volume of water + gold) – (Volume of water)

Volume of gold = 19.4 – 12

Volume of gold = 7.4 mL

Finally, we shall determine the mass of the gold as follow:

Note: 1 mL is equivalent to 1 cm³

Volume of gold = 7.4 mL

Density of gol= 19.3 g/cm³ = 19.3 g/mL

Mass of gold =?

Density = mass /volume

19.3 = mass of gold /7.4

Cross multiply

Mass of gold = 19.3 × 7.4

Mass of gold = 142.82 g

Therefore, the mass of the gold pebble is 142.82 g

6 0
3 years ago
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