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mario62 [17]
4 years ago
6

Which orbital do potassium's outermost electrons occupy? 4s 4p 4d 3s

Chemistry
2 answers:
olga_2 [115]4 years ago
5 0
Potassium's outermost electrons occupy the 4s orbital because potassium is in the s column of the 4th period.
Elanso [62]4 years ago
4 0
Potassium outermost electron occupy "4s" orbital
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Both protons and neutrons (and their anti-particles) froze out:
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I think Both protons and neutrons (and their anti-particles) froze out at 1013 K, about 0.0001 seconds after the Big Bang. Protons and neutrons are sub atomic particles of an atom that are found in the nucleus of an atom. Proton is the positively charge particle while the neutron has no charge. The proton positive charge accounts for the positive nuclear charge. 
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A student makes a sandwich with several layers of bread and cheese. Then the student cuts the sandwich and says it models how a
Ksenya-84 [330]

Answer:

Rock layer and sandwich layer is almost the same.

Why are rock layers are like sandwiches?

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3 years ago
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ollegr [7]

Answer:

The answer to your question would be "the insect touching the trigger hairs".

Explanation:

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8 0
3 years ago
Read 2 more answers
¿Cuál de los siguientes no es un ejemplo de movimiento de masas?
babunello [35]

Which of the following is not an example of a mass movement?

to. a. Ground slides  b) acid rain  c. mud flow  d. drop

Answer:

b) acid rain

Explanation:

Acid rain is not an example or a type of mass movement.

Mass movement or mass wasting is the movement of rocks, soils and other debris downslope under the influence of gravity.

Water, slope and gravity are triggers of mass movement.

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8 0
3 years ago
Determine the heat energy needed to raise the temperature of 120 grams of ice at -5 to steam at 115°
CaHeK987 [17]

Answer:

Q = 30355.2 J

Explanation:

Given data:

Mass of ice = 120 g

Initial temperature = -5°C

Final temperature = 115°C

Energy required = ?

Solution:

Specific heat capacity of ice is = 2.108 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Q = m.c. ΔT

ΔT = T2 -T1

ΔT = 115 - (-5°C)

ΔT = 120 °C

Q = 120 g × 2.108 j/g.°C × 120 °C

Q = 30355.2 J

5 0
3 years ago
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