The correct answer is B,
<span>It is endothermic, with both positive enthalpy and entropy changes.</span>
Answer:
0.02405 g/L is the solubility of argon in water at 25 °C.
Explanation:
Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.
To calculate the molar solubility, we use the equation given by Henry's law, which is:
![C_{Ar}=K_H\times p_{gas}](https://tex.z-dn.net/?f=C_%7BAr%7D%3DK_H%5Ctimes%20p_%7Bgas%7D)
where,
= Henry's constant = ![1.40\times 10^{-3}mol/L.atm](https://tex.z-dn.net/?f=1.40%5Ctimes%2010%5E%7B-3%7Dmol%2FL.atm)
= partial pressure of carbonated drink = 0.51atm
Putting values in above equation, we get:
![C_{Ar}=1.40\times 10^{-3}mol/L.atm\times 0.430 atm\\\\C_{Ar}=6.02\times 10^{-4}mol/L](https://tex.z-dn.net/?f=C_%7BAr%7D%3D1.40%5Ctimes%2010%5E%7B-3%7Dmol%2FL.atm%5Ctimes%200.430%20atm%5C%5C%5C%5CC_%7BAr%7D%3D6.02%5Ctimes%2010%5E%7B-4%7Dmol%2FL)
Molar mass of argon = 39.95 g/mol
Solubility of the argon gas :
![6.02\times 10^{-4}mol/L\times 39.95 g/mol=0.02405 g/L](https://tex.z-dn.net/?f=6.02%5Ctimes%2010%5E%7B-4%7Dmol%2FL%5Ctimes%2039.95%20g%2Fmol%3D0.02405%20g%2FL)
0.02405 g/L is the solubility of argon in water at 25 °C.
Concentration of a solution can be expressed in terms of molarity and molality
Molarity is the number of moles of solute in a liter of a solution.
Molarity (M) = Moles of solute/Volume(litres) of solution
Molality is the number of moles of solute in one kg of the solution
Molality (m) = Moles of solute/Mass (kg) of solution
Therefore if the volume or the mass of the solution is changed this would affect the concentration.
In addition, volume is a quantity which depends on temperature. However, mass is independent of temperature. Therefore any changes in temperature, can also bring about a change in the molarity of the solution.
Answer:
mass of HCl = 243.5426 grams
Explanation:
1- we will get the mass of the reacting gold:
volume of gold = length * width * height
volume of gold = 3.2 * 3.8 * 2.8 = 34.048 cm^3 = 34.048 ml<span>
density = mass / volume
Therefore:
mass = density * volume
mass of gold = </span>19.3 * 34.048 = 657.1264 grams
2- we will get the number of moles of the reacting gold:
number of moles = mass / molar mass
number of moles = 657.1264 / 196.96657
number of moles = 3.3362 moles
3- we will get the number of moles of the HCl:
First, we will balanced the given equation. The balanced equation will be as follows:
Au + 2HCl ......> AuCl2 + H2
This means that one mole of Au reacts with 2 moles of HCl.
Therefore 3.3362 moles will react with 2*3.3362 = 6.6724 moles of HCL
4- we will get the mass of the HCl:
From the periodic table:
molar mass of H = 1 gram
molar mass of Cl = 35.5 grams
Therefore:
molar mass of HCl = 1 + 35.5 = 36.5 grams/mole
number of moles = mass / molar mass
Therefore:
mass = number of moles * molar mass
mass of HCl = 6.6724 * 36.5
mass of HCl = 243.5426 grams
Hope this helps :)
Answer:
left to right across a period when it decreases and when it increases top to bottom in a group,
hope i helped