Answer:
It would be 2 whole pizza left for the adults. the improper fraction would be 2 1/2 or 5/2
Step-by-step explanation:
Answer:
Step-by-step explanation:
see the attached figure with letters to better understand the problem
step 1
In the right triangle ACD
Find the length side AC
Applying the Pythagorean Theorem
substitute the given values
simplify
step 2
In the right triangle ACD
Find the cosine of angle CAD
substitute the given values
----> equation A
step 3
In the right triangle ABC
Find the cosine of angle BAC
substitute the given values
----> equation B
step 4
Find the value of x
In this problem
----> is the same angle
so
equate equation A and equation B
solve for x
Multiply in cross
step 5
Find the length of BC
In the right triangle BCD
Applying the Pythagorean Theorem
substitute the given values
simplify
Since J is the midpoint of HK, that means HK is split into two sections HJ and JK that are the same length.
1) You are told that the m<span>easure of segment HJ = 9x-2 and that of segment JK = 4x+13. Since you also know they are equal lengths, you can set these equations equal to each other to find the value of x!
HJ = JK
</span>9x-2 = 4x+13
5x = 15
x = 3
2) Now you know x = 3. Plug that into your given equations for HJ and JK to find the length of each segment (or a shortcut would be to find one of them, and then you also know the other is the same length. I'm doing both, just to make sure I don't make a silly mistake!):
HJ = <span>9x-2
</span>HJ = 9(3) - 2
HJ = 27 - 2
HJ = 25
JK = 4x + 13
JK = 4(3) + 13
JK = 12 + 13
JK = 25
3) Finally, the length of HK is just the length of HJ + JK, or HK = 25 + 25 = 50.
-----
Answer: HJ = 25, JK = 25, HK = 50
Answer:
52
Step-by-step explanation:
13 = x/4
To isolate the x, you have to multiply 4 on each side.
x/4 * 4= x
13 * 4 = 52
x = 52
Answer: Ann = 67 Josh = 60 Claire = 30
Step-by-step explanation: You get the equation 5x+7 = 157. You get the equation because for example, Claire = x then josh = 2x and Ann = 2x + 7. You do all the math and boom! You get the answer :)
