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Fudgin [204]
2 years ago
15

if u know anything about force and acceleration please help lol I didn't pay attention to this on 8th grade (no links pls)

Physics
1 answer:
Alex_Xolod [135]2 years ago
5 0

Answer:

Im not fully sure but i think its  

red

green

purple

yellow

blue

Explanation:

because the more mass the less acceleration hopefully im right on this

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A drill has a density of 11.342 g/cm3. Its mass is 1500 g. What is the volume of the drill? Round to TWO decimal places.
Andrews [41]

Explanation:

11.342=1500/ volume

volume=1500/11.342

volume=132.25cm³

3 0
3 years ago
The surface of the dock is 6 feet above the water. If you pull the rope in at a rate of 2 ft/sec, how quickly is the boat approa
Oduvanchick [21]

Answer:

The boat is approaching the dock at a rate of <u>2.5 ft/s</u>.

Explanation:

Let the rope length be 'l' at any time 't', the distance of boat from dock be 'b' at any time 't'.

Given:

The height of dock above water (h) = 6 feet

Rate of pull of rope or rate of change of rope is, \frac{dl}{dt}=2\ ft/s

As clear from the question, the height is fixed and only the length 'l' and distance 'b' varies with time 't'.

Now, the above situation represents a right angled triangle as shown below.

Using Pythagoras Theorem, we have:

l^2=h^2+b^2\\\\l^2=6^2+b^2\\\\l^2=36+b^2----------(1)

Now, differentiating the above equation with time 't', we get:

2l\frac{dl}{dt}=0+2b\frac{db}{dt}\\\\l\frac{dl}{dt}=b\frac{db}{dt}\\\\\frac{db}{dt}=\frac{l}{b}\frac{dl}{dt}------(2)

Now, the distance 'b' can be calculated using 'l=10 ft' in equation (1). This gives,

b^2=10^2-36\\\\b=\sqrt{64}=8\ ft

Now, substituting all the given values in equation (2) and solve for \frac{db}{dt}. This gives,

\frac{db}{dt}=\frac{10}{8}\times 2\\\\\frac{db}{dt}=2.5\ ft/s

Therefore, the boat is approaching the dock at a rate of 2.5 ft/s.

7 0
3 years ago
How often does a 16-year-old need a medical evaluation from a doctor?
a_sh-v [17]

Answer:

Explanation: A

5 0
4 years ago
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When we use an analogy that represents the expanding universe with the surface of an expanding balloon, what does the inside of
svetlana [45]

Answer:  When we use an analogy that represents the expanding universe with the surface of an expanding balloon, what does the inside of the balloon represent? The inside of the balloon does not represent any part of our universe.

7 0
3 years ago
Physics, calculating net force. Please work it out for me
Margarita [4]

Answer:

F = 2985.125 N

Explanation:

Given that,

The radius of curvature of the roller coaster, r = 8 m

Speed of Micheal, v = 17 m/s

Mass of body, m = 65 kg  We need to find the net force acting on Micheal. Net force act the bottom of the circle is given by :

F=\dfrac{mv^2}{r}+mg\\\\F=m(\dfrac{v^2}{r}+g)\\\\=65(\dfrac{17^2}{8}+9.8)\\\\=2985.125\ N

So, the net force is 2985.125 N.

3 0
3 years ago
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