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3 years ago

Which of the following demonstrates a translation?

Physics

2 answers:

Ivan3 years ago

8 0

A translation means moving something up down or left/right

Lets use that definition to figure the answer out

A). A spinning Wheel

No, because it is spinning, not moving up or down left/right

B). a child swinging on a swing

No because the child is in a swinging state of motion, not left or right, or up or down.

C). The blade of a kitchen blender

No, because it is in a spinning motion, which we ruled out to be incorrect previously.

Therefore the correct choice is

<h2>D) A sliding hockey puck</h2>

Why?

A sliding puck is always moving left or right, view the hockey field as an XY plane, and it is being translated left & right.

DaniilM [7]3 years ago

3 0

Definitely D.

Hope this helps

You might be interested in

A cricket can travel approximately 8 m/s. How many meters could a cricket travel in 75<br> s?

nika2105 [10]

Answer:

Your answer will be 600meters

7 0

3 years ago

On earth, what is a child’s mass if the force of gravity on the child’s body is 100 N

ikadub [295]

Answer: 10.2 kg if g = 9.8, 10 if g = 10.

Explanation:

Weight or the "force of gravity" on a person is simply defined by the equation: F = ma. In this case, the acceleration is g, which is 9.8 but can be rounded up to 10. Based on this, we have:

F = mg

100 = m*9.8

m = 10.2(or 10 if we set g to 10).

4 0

3 years ago

Two friends, Al and Jo, have a combined mass of 195 kg. At the ice skating rink, they stand close together on skates, at rest an

ddd [48]

Answer:

Al's mass is 102.92 kg

Explanation:

As there are no external forces in the horizontal direction, the horizontal net force must be zero:

$F_{net} = 0$

As the force is the derivative in time of the momentum, this means that the horizontal momentum is constant:

$F_{net} = \frac{dp_{horizontal}}{dt} = 0$

$p_{horizontal_i }= p_{horizontal_f}$

where the suffix i and f means initial and final respectively.

The initial momentum will be:

$p_{horizontal_}i = m_{Al} \ v_{Al_i} + m_{Jo} \ v_{Jo_i}$

But, as they are at rest, initially

$p_{horizontal_i} = m_{Al} * 0 + m_{Jo} * 0$

$p_{horizontal_i} = 0$

So, this means:

$p_{horizontal_f} = m_{Al} \ v_{Al_f} + m_{Jo} \ v_{Jo_f} = 0$

We know that the have an combined mass of 195 kg:

$m_{total} = m_{Al} + m_{Jo} = 195 \ kg$ .

so:

$m_{Jo} = 195 \ kg - m_{Al}$ .

$m_{Al} \ v_{Al_f} + (195 \ kg - m_{Al}) \ v_{Jo_f} = 0$

$m_{Al} \ v_{Al_f} - m_{Al} \ v_{Jo_f}= - 195 \ kg \ v_{Jo_f}$

$m_{Al} \ (v_{Al_f} - v_{Jo_f})= - 195 \ kg \ v_{Jo_f}$

$m_{Al} = \frac{ - 195 \ kg \ v_{Jo_f} } { v_{Al_f} - v_{Jo_f} }$

$m_{Al} = \frac{195 \ kg \ v_{Jo_f} } { v_{Jo_f} - v_{Al_f} }$

Now, we can use the values:

$v_{Al_f}= 10.2 \frac{m}{s}$

$v_{Jo_f}= - 11.4 \frac{m}{s}$

where the minus sign appears as they are moving at opposite directions

$m_{Al} = \frac{195 \ kg ( - 11.4 \frac{m}{s} ) } { (- 11.4 \frac{m}{s}) - 10.2 \frac{m}{s} }$

$m_{Al} = 102.92 \ kg$

and this is the Al's mass.

5 0

3 years ago

Geologists apply various methods to study the layers of the Earth. Which of the following is NOT a method used to study the Eart

77julia77 [94]

Answer:

A. Scientists use seismic computer models to measure the atmospheric conditions above the Earth's crust

Explanation:

why would use atmosphere to study the layers of earth? dont think thats possible

8 0

3 years ago

The steering wheel of a car has a radius of 0.19 m, and the steering wheel of a truck has a radius of 0.25 m. The same force is

kodGreya [7K]

Answer:

$\frac{T_t}{T_c} = 1.32$

Explanation:

The torque applied on an object can be calculated by the following formula:

$T = Fr$

where,

T = Torque

F = Applied Force

r = radius of the wheel

For car wheel:

$T_c = Fr_c\\$

For truck wheel:

$T_t = Fr_t$

Dividing both:

$\frac{T_t}{T_c} = \frac{Fr_t}{Fr_c}$

for the same force applied on both wheels:

$\frac{T_t}{T_c} = \frac{r_t}{r_c} \\$

where,

rt = radius of the truck steering wheel = 0.25 m

rc = radius of the car steering wheel = 0.19 m

Therefore,

$\frac{T_t}{T_c} = \frac{0.25\ m}{0.19\ m} \\$

$\frac{T_t}{T_c} = 1.32$

8 0

3 years ago