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Ulleksa [173]
4 years ago
12

Find the voltage across and power absorbed by the 25 ohm resistor.

Physics
1 answer:
frozen [14]4 years ago
8 0
S s. A sbsbs s sbsbbsbss s s
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The change from a solid to a liquid occurs at _____.
NNADVOKAT [17]
At the melting point
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3 years ago
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Container A and container B hold samples of the same ideal gas. The volume and the pressure of container A is equal to the volum
SVETLANKA909090 [29]

Answer:

A. TA = TB/2.

Explanation:

Since container A has half as many molecules of the ideal gas in it as container B. Therefore, container A will have half the volume of gas as in container B:

V_A = \frac{1}{2}V_B

Now, from Charle's Law:

\frac{V_A}{T_A}=\frac{V_B}{T_B}\\\\\frac{1}{2}\frac{V_B}{T_A}=\frac{V_B}{T_B}\\\\T_A = \frac{T_B}{2}

Hence, the correct option is:

<u>A. TA = TB/2.</u>

6 0
3 years ago
When an electron jumps from high-to low-energy levels:
AysviL [449]

Answer:

B. A wave of visible light is produced.

Explanation:

The visible light spectrum is in the centre of the Electromagnetic Spectrum, so any time an electron jumps from high to low levels of radiation, it has to cross through the visible spectrum.

I hope this is correct, and as always, I am joyous to assist anyone at any time.

5 0
4 years ago
Which of the following describes one of Galileo Galilei's contributions to the development of the concept of gravity?
BARSIC [14]

Answer:

The correct option is;

c. He conducted experiments with balls and inclined planes

Explanation:

The inclined plane experiment conducted by Galileo Galilei was one of his most important experiments.

The experiment consisted of a grooved board with which a small metal ball is rolled down in, so as to analyze the held Aristotelian ideas about motion.

In the experiment, the focus was on acceleration, a concept that the previously held ideas about motion

4 0
3 years ago
A tennis ball with a speed of 11.3 m/s is moving perpendicular to a wall. after striking the wall, the ball rebounds in the oppo
Arlecino [84]

To calculate the average acceleration of the ball we use the formula,

a= \frac{v_{f} -v_{i}}{t}

Here, v_{f} is the final velocity of the ball and v_{i} is the initial velocity of the ball t is the time in contact with the wall.

Given v_{i} = 11.3 m/s towards the wall and v_{f} = 7.2207 m/s

away from the wall and t=0.00803 s.

Substituting these values in above formula , we get

a=\frac{(-7.2207 m/s)-11.3 m/s}{0.00803 s}

Herev_{f} is negative because ball is moving away from the wall.

a= - 2306 .4 \ m/s^{2}

Therefore, average acceleration of the ball is - 2306 .4 \ m/s^{2} (away from the wall).

 

4 0
4 years ago
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