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2 years ago

To which layer can geologists apply the principle of faunal succession to determine the age of the layer?

Physics

2 answers:

Klio2033 [76]2 years ago

8 0

This question looks familiar. Maybe layer A?

vlabodo [156]2 years ago

5 0

Answer:

Layer C

Explanation:

The Principle of faunal succession also is the study of fossils

Their for making the answer A

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In traveling a distance of 2.5 km between points A and D, a car is driven at 99 km/h from A to B for t seconds and 48 km/h from

Andreyy89

Answer:

d = 1.954 Km

Explanation:

given,

total distance, D = 2.5 Km

in stretch A to B =

speed = 99 Km/h = 99 x 0.278 = 27.22 m/s time =t

in stretch B to C

time = 3.4 s

In stretch C to D

speed = 48 Km/h = 48 x 0.278 = 13.34 m/s time =t

we know,

distance = speed x time

distance of BC

using equation of motion

v = u + a t

27.22 = 13.34 - a x 3.4

a = 4.08 m/s²

uniform deceleration is equal to 4.08 m/s²

distance traveled in BC

$s = ut + \dfrac{1}{2}at^2$

$s = 13.34\times 3.4 + \dfrac{1}{2}\times 4.08 \times 3.4^2$

s = 68.94 m

$3000 = 99 \times \dfrac{1000\ t}{3600}+ 68.94 + 48\times \dfrac{1000\ t}{3600}$

3000 = 27.5 t + 68.94 + 13.33 t

40.83 t = 2931.06

t = 71.79 s

distance travel in AB

distance = s x t

d = 27.22 x 71.79

d = 1954 m

d = 1.954 Km

distance between A and B is equal to 1.954 Km.

4 0

3 years ago

Which is a correct reason to physically connect objects with a bond wire when transferring flammable liquids? A. To create a pat

RideAnS [48]

<h2>When Transferring Flammable Liquids - Option A</h2>

To create a pathway for the liquid to flow easily is a correct reason to physically connect objects with a bond wire when transferring flammable liquids. Physically connect the two conductive objects together with a bond wire to eliminate a difference in static charge potential among them. The bond wire is attached between the containers in the process of flammable filling liquid actions except for a metallic path is found.

5 0

3 years ago

Read 2 more answers

Show that (a)KE=1/2mv2

evablogger [386]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{see \: below}}}}}$

Explanation:

$\underline{ \bold{ \sf{To \: prove \: that \: kinetic \: energy = \frac{1}{2} m {v}^{2} }}}$

Let us consider, a body of mass ' m ' is lying at rest ( initial velocity = 0 ) on a smooth surface. Let a constant force F displaces this body in its own direction by a displacement ' d '. Let 'v' be it's final velocity. The work done ' W ' by the force is given by :

$\sf{W = FD}$

⇒ $\sf{W = m \: \times a \: \times s} \: \: \: \: \: \: \: \: \: ( \: ∴ \: f \: = \: ma \: ; \: s \: = d)$

⇒ $\sf{W = m \: \times \frac{v - u}{t} \times \frac{u + v}{2} \times t \: \: \: \: \: \: \: \: \: (∴ \: a = \frac{v - u}{t} and \: s = \frac{u + v}{2} \times t}$

⇒ $\sf{W = m \times \frac{ {v}^{2} - {u}^{2} }{2} }$

⇒ $\sf{W = \frac{1}{2} m {v}^{2} \: \: \: \: \: \: \: \: \: \: \: \: (since, \: initial \: velocity(u) = 0)}$

The work done becomes the kinetic energy of the body. Thus, the kinetic energy of a body of mass ' m : moving with the velocity equal to 'v ' is 1 / 2 mv²

∴ $\sf{KE= \frac{1}{2} m {v}^{2} }$

$\sf{ \underline{ \bold{ {proved}}}}$

Hope I helped!

Best regards!!

5 0

3 years ago

A cylindrical tank of methanol has a mass of 70 kg and a volume of 75 L. Determine the methanol’s weight, density, and specific

dem82 [27]

Answer:

Weight=686.7N, $\rho=933kg/m^{3}$ , S.G.=0.933, F=17.5N

Explanation:

So, the first value the problem is asking us for is the weight of methanol. (This is supposing there is a mass of methanol of 70kg inside the tank). We can find this by using the formula:

W=mg

so we can substitute the data the problem provided us with to get:

$W=70kg(9.81m/s^{2})$

which yields:

W=686.7N

Next, we need to find the density of methanol, which can be found by using the following formula:

$\rho=\frac{m}{V}$

we know the volume of methanol is 75L, so we can convert that to $m^{3}$ like this:

$75L*\frac{0.001m^{3}}{1L}=0.075m^{3}$

so we can now use the density formula to find our the methanol's density, so we get:

$\rho=\frac{m}{V}$

$\rho=\frac{70kg}{0.075m^{3}}$

$\rho=933.33kg/m^{3}$

Next, we can us these values to find the specific gravity of methanol by using the formula:

$S.G.=\frac{\rho_{sample}}{\rho_{H_{2}O}}$

when substituting the known values we get:

$S.G.=\frac{933.33kg/m^{3}}{1000kg/m^{3}}$

so:

S.G.=0.933

We can now find the force it takes to accelerate this tank linearly at $0.25m/s^{2}$

F=ma

$F=(70kg)(0.25m/s^{2})$

F=17.5N

6 0

3 years ago

What force causes centripetal acceleration of a car making a turn on a flat road?

Stella [2.4K]

The force that causes centripetal acceleration of a car making a turn on a flat road is friction

The centripetal acceleration is required to create a centripetal force. The centripetal force that cause an object to turn in a circular path is due to the force of friction between the tyres and the road. The magnitude of centripetal force is numerically equal to the magnitude of frictional force.

Fc = f

m v² / r = μ N

Fc ∝ 1 / r

The larger the centripetal force the the smaller the radius of curvature.

Therefore, the force that causes centripetal acceleration of a car making a turn on a flat road is friction

To know more about centripetal force

brainly.com/question/11324711

#SPJ9

3 0

11 months ago