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3 years ago

To which layer can geologists apply the principle of faunal succession to determine the age of the layer?

Physics

2 answers:

Klio2033 [76]3 years ago

8 0

This question looks familiar. Maybe layer A?

vlabodo [156]3 years ago

5 0

Answer:

Layer C

Explanation:

The Principle of faunal succession also is the study of fossils

Their for making the answer A

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A positive charge of 1 µC is taken from points A & B such that VA-VB = 100 V. Then the

Lunna [17]

Explanation:

It is given that,

Let Charge of $1\ \mu C$ is taken from points A & B such that $V_A-V_B=1000\ V$ .

We need to find the energy of charge. Electric potential is defined as the work done per unit of electric charge. So,

$W=(V_B-V_A)q\\\\W=-1000\times 10^{-6}\\\\W=E=-10^{-3}\ J$

So, the energy of charge decreases by $10^{-3}\ J$ . Hence, the correct option is (a).

4 0

3 years ago

a car takes 1 hour to travel 100 km along a main road and the half hour to travel 20 km along a side road what is its average sp

kolezko [41]

80 km per hour i believe. i’ll admit i’m american so we don’t use km lol, but the math should be the same. total distance = 120km, and total time = 1.5 hours. 120/1.5 = 80.

3 0

3 years ago

A uniform stick 1.5 m long with a total mass of 250 g is pivoted at its center. A 3.3-g bullet is shot through the stick midway

Andru [333]

Answer:

63.44 rad/s

Explanation:

mass of bullet = 3.3 g = 0.0033 kg

initial velocity of bullet $v_{1}$ = 250 m/s

final velocity of bullet $v_{2}$ = 140 m/s

loss of kinetic energy of the bullet = $\frac{1}{2}m(v^{2} _{1} - v^{2} _{2})$

==> $\frac{1}{2}*0.0033*(250^{2} - 140^{2} )$ = 70.785 J

this energy is given to the stick

The stick has mass = 250 g =0.25 kg

its kinetic energy = 70.785 J

from

KE = $\frac{1}{2} mv^{2}$

70.785 = $\frac{1}{2}*0.25*v^{2}$

566.28 = $v^{2}$

$v= \sqrt{566.28}$ = 23.79 m/s

the stick is 1.5 m long

this energy is impacted midway between the pivot and one end of the stick, which leaves it with a radius of 1.5/4 = 0.375 m

The angular speed will be

Ω = v/r = 23.79/0.375 = 63.44 rad/s

5 0

3 years ago

If a car goes around a corner at a constant 20 miles/hour, does its velocity change?

UNO [17]

Answer:

yes

Explanation:

velocity changes either in magnitude (an increase or decrease in speed) or in direction, or both

3 0

3 years ago

Read 2 more answers

suppose the same chest is at rest. you push it horizontally with force of 110N but it does not budge. What is the contact force

Radda [10]

Answer:

110 N

Explanation:

When a force is applied on a body and body does not move, it means the body remains at rest.

In this condition, there is a contact force between the body and the floor which is called static friction.

Th static friction force is a self adjusting force and comes into play when the body is at rest.

Here, the applied force is 110 N and the chest is not moving, that means a static friction force is acting between the chest and the floor. This static friction force is the force of contact between the chest and the floor. The static friction force is equal to the applied force when the body does not move.

So, the contact force between the chest and the floor is 100 N.

4 0

3 years ago