Answer:
15.7 m
Explanation:
The range (horizontal distance) of the projectile is determined only by its horizontal motion.
The horizontal motion is a motion with constant speed, which is equal to the initial horizontal velocity of the object:
where
v = 12.0 m/s is the initial velocity
is the angle between the direction of v and the horizontal
Substituting,
We know that the projectile hits the ground in a time of
t = 2.08 s
so the horizontal distance covered is
Answer:
Coefficient of friction between the book and floor is 0.582.
Explanation:
Using the velocity formula;
v^2 = 2as
a = v^2/(2s)
a = 1.6^2/(2*0.9)
a = 2.56/1.8
a = 1.42 m/s^2
the force necessary to give the book the acceleration is
F = ma = 3.5*1.42 (m is mass of the book i.e. 3.5 kg)
F = 4.98 N
The difference in the force is the friction force, which is
Ff = 25 - 4.98 = 20 N
Ff = mgμ
where μ is coefficient of friction and g is acceleration due to gravity that is 9.8 m/s^2
μ = Ff/mg
μ = 20/(3.5*9.81)
μ = 0.582
Coefficient of friction between the book and floor is 0.582.
Answer:
The net force applied to the car is zero.
Explanation:
We are given that a car is moving to the left with constant velocity.
When the car moving with constant velocity
Then, the final velocity=Initial velocity
Change in velocity=Final velocity- initial velocity=0
When change in velocity is zero then , acceleration of car
When acceleration is zero then, By Newtons second law
The net force applied on the car will be zero.
Option C:The net force applied to the car is zero.
Answer:
365 days
So The Final Answer is a Year
D is the answer
Explanation:
Answer:
R = 6.8
Explanation:
Given data:
Richter scale
where R - magnitude of earthquake of Richter scale
I - quake's intensity
- minimum intensity earthquake
Plugging all information in the equation to get Richter's scale
R = 6.8