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Snowcat [4.5K]
3 years ago
15

The largest jaw breaker in a store is spherical with a radius of 2 in. and sells for $4.00. A

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
3 0

Answer:

$12

Step-by-step explanation:

Given data

Radius= 2in

cost = $4

New jaw breaker radius= 6in

cost=???

If 2 in jaw breaker cost $4

6in jaw breaker will cost x

cross multiply

6*4= 2*x

24= 2x

x= 24/2

x= $12

Hence the 6 in jawbreaker will cost $12

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Answer:

G = 2/3

Step-by-step explanation:

-13G + 10 = 2(-5G + 4)  Distribute the 2 to (-5G + 4)

-13G + 10 = -10G + 8  

+13G           +13G         Add 13G to both sides

10 = 3G + 8

-8           -8                  Subtract 8 from both sides

2 = 3G                          Divide both sides by 3

2/3 = G

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Which relationship describes angles 1 and 2?
Alchen [17]
They are adjacent angles

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No links pls
Jobisdone [24]

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Step-by-step explanation:

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3 years ago
How do i put this into words please help
Serjik [45]
Hello,

This is simple :)

<span>First divide:

How many times does 16 go into 7? : 0

7 GOES into 16, 0 times, now we have ; 0.

Next, multiply 16(0):0

Now, subtract 7-0

=7

Bring 0 down... so now we have 70... how many times can you divide 16 into 70? : about 4 times.

Now we have: 0.4

Multiple 16 by 4

= 64 : SUBTRACT 64 from 70

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Bring Down: 0; this gives us 60.

Divide:

How many times can 16 go into 60? : About 7 times

No we have : 0.437..

Bring down 0; gives us 600: how many times can 16 go into 600?: About 5 times.

Now, we have 0.4375.


Thus, 7/16 = 0.4375.


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The midpoints of the hexagon are connected to form another hexagon, this pattern continues indefinitely. If the area of the 99th
jarptica [38.1K]

Answer:

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Step-by-step explanation:

  • <em>Regular hexagons have a property that cutting off the triangles obtained by joining the midpoints of consecutive sides leaves a hexagon of 3/4 of the area.</em>

This means the area of each hexagon inside out starting from the one with unit area is 4/3 of the previous one.

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<u>The original hexagon has the area of:</u>

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