All categories

3 years ago

What is the ground state electron configuration of a neutral atom of titanium

Chemistry

1 answer:

muminat3 years ago

3 0

Answer:

Explanation:

the ground state electron configuration of ground state gaseous neutral titanium is [Ar]. 3d2. 4s2 and the term symbol is 3F2.

You might be interested in

Determine the molar solubility of pbso4 in pure water. ksp (pbso4) = 1.82 x 10-8.

Misha Larkins [42]

Use the ICE table approach as solution:

PbSO₄ --> Pb²⁺ + SO₄²⁻
I - 0 0
C - +s +s
E - s s

Ksp = [Pb²⁺][SO₄²⁻]
1.82×10⁻⁸ = s²
Solving for s,
s = 1.35×10⁻⁴ M

5 0

3 years ago

He standard reduction potentials of lithium metal and chlorine gas are as follows: reaction reduction potential (v) li+(aq)+e−→l

AURORKA [14]

2 Li(s) +Cl₂→ 2 Li⁺ (aq) + 2Cl⁻ (aq)

The cell potential of the reaction above is +4.40V

calculation

Cell potential =∈° red - ∈° oxidation

in reaction above Li is oxidized from oxidation state 0 to +1 therefore the∈° oxid = -3.04

Cl is reduce from oxidation state 0 to -1 therefore the ∈°red = +1.36 V

cell potential is therefore = +1.36 v -- 3.04 = + 4.40 V

3 0

3 years ago

What happens when acetylene reacts with silver powder?

horrorfan [7]

It dissolves I think I know I am expert and. Ute

6 0

2 years ago

The town of Natrium, West Virginia, derives its name from the sodium produced in the electrolysis of molten sodium chloride (NaC

Alona [7]

Explanation:

The reaction equation will be as follows.

$Na^{+} + e^{-} \rightarrow Na(s)$

Hence, moles of Na = moles of electron used

Therefore, calculate the number of moles of sodium as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{4500 g}{23 g/mol}$ (as 1 kg = 1000 g)

= 195.65 mol

As, Q = $n \times F$ where F = Faraday's constant

= $195.65 mol \times 96500 C$

= $1.88 \times 10^{7}$ mol C

Relation between electrical energy and Q is as follows.

E = $Q \times V$

Hence, putting the given values into the above formula and then calculate the value of electricity as follows.

E = $Q \times V$

= $1.88 \times 10^{7} \times 5$

= $9.4 \times 10^{7} J$

As 1 J = $2.77 \times 10^{-7}$ kWh

Hence, $\frac{9.4 \times 10^{7}}{2.77 \times 10^{-7}}$ kWh

= 3.39 kWh

Thus, we can conclude that 3.39 kilowatt-hours of electricity is required in the given situation.

7 0

3 years ago

Read 2 more answers

How do polar molecules respond when they are placed between two metal plates, one positively charged and one negatively charged?

kakasveta [241]

Gradpoint

The molecules align to the electric field

5 0

3 years ago

Read 2 more answers