Ask question

Ask question

All categories

2 years ago

11

In a laboratory experiment, john uses a message to seperate soil particles from water . Which technique separation which techniq

ue of separation is he using

1 answer:

eimsori [14]2 years ago

3 0

So visualize soil mixed with water. To separate it, you can use a sieve to filter the water.

You might be interested in

How many grams of sodium nitrate (NaNO2) will dissolve in 100g of water at 20°C?

inn [45]

88g ( so sorry if this isn’t correct )

8 0

2 years ago

Which of the following solutions is more concentrated?<br> 0.50M KCl or 5.0% (w/v) KCl

HACTEHA [7]

.50 M KCl because 5% is the same as .05, which makes the .50M more concentrated.

6 0

2 years ago

Determine the number of moles of iodine that reacts with 50g of aluminum

frozen [14]

Answer: The correct answer is option B i.e., 2.78 mol

Explanation:

Aluminium reacts with iodine to form Aluminium iodide

$2Al(s)+3I_{2}(s) \to Al_{2}I_{6}(s)$

From the equation, it is clear that 3 moles of iodine reacts with 2 moles of Aluminium to form Aluminium iodide

We know $$No.\,of\,moles=\frac{weight}{molecular\,weight} \\$

For 2 moles of Aluminium, $2=\frac{weight}{27}$\\ $weight=2 \times 27=54g$

3 moles of Iodine reacts with 54 g of Aluminium

? moles of iodine react with 50 g of Aluminium

$=\frac{3 \times 50}{54} =2.78 mol$

8 0

2 years ago

A certain metal M crystallizes in a lattice described by a body-centered cubic (bcc) unit cell. The lattice constant (a, the edg

Furkat [3]

Answer:

radius = 156 pm

Explanation:

The relation between radius and edge length of unit cell of BCC is

r=a $\sqrt{3}$ /4

Given

a = 360 pm

Therefore

r = r = radius = 360 $\sqrt{3}$ /4= 155.88 pm

Or

156 pm

3 0

2 years ago

When you have a free metal ion, how do the energies of these orbitals relate to one another (are they the same, different, etc.)

7nadin3 [17]

Answer:

The energy of the orbitals are the same

Explanation:

For a free metal ion, all the d-orbitals are of the same energy. The five d-orbitals are said to be five fold degenerate in the free metal ion. Hence all the d-orbitals will possess the same energy irrespective of which one is first filled.

In an octahedral or tetrahedral crystal field, the d-orbitals will loose their degeneracy and become different in energy based on their orientation towards the ligands.

4 0

3 years ago