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3 years ago

Which flow diagram best explains the energy transformations that occur within an automobile running on diesel

1 answer:

5 0

In diesel engines, the chemical energy in the fuel is changed to heat energy, causing the pistons to expand via mechanical energy. The mechanical energy is finally converted to kinetic energy, which is observed as the movement of the vehicle.

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Elena L [17]

Answer:

no it should not that place is historical and so they should make where u can visit but protect it as a historical landmark

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3 years ago

How are the carbon, oxygen, and nitrogen cycles vital to sustaining life on Earth?. a.. Carbon, oxygen, and nitrogen are vital c

kumpel [21]

The correct answer is (D)

All the above are reasons the carbon , oxygen, and nitrogen cycles are vital to life on earth.

The explanation:

because :

1) Carbon, oxygen, and nitrogen are vital components of life on Earth.

2) The carbon, oxygen, and nitrogen cycles allow vital elements to return to usable form by organisms.

3)The carbon, oxygen, and nitrogen cycles are an important interface between biotic and abiotic factors

4) They are all biogeochemical cycles.

5) They all involve an interaction between living and nonliving elements.

6)They are all part of the Earth system.

5 0

3 years ago

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If acetic acid is the only acid that vinegar contains (ka=1.8×10−5), calculate the concentration of acetic acid in the vinegar.

kicyunya [14]

Ethanoic (Acetic) acid is a weak acid and do not dissociate fully. Therefore its equilibrium state has to be considered here.

$CH_{3}COOH \ \textless \ ---\ \textgreater \ H^{+} + CH_{3}COO^{-}$

In this case pH value of the solution is necessary to calculate the concentration but it's not given here so pH = 2.88 (looked it up)

pH = 2.88 ==> $[H^{+}]$ = $10^{-2.88}$ = 0.001 $moldm^{-3}$

The change in Concentration Δ $[CH_{3}COOH]$ = 0.001 $moldm^{-3}$

  CH3COOH H+ CH3COOH
Initial   $moldm^{-3}$      $x$ 0 0

Change $moldm^{-3}$ -0.001 +0.001 +0.001

Equilibrium $moldm^{-3}$ $x$ - 0.001 0.001 0.001


Since the $k_{a}$ value is so small, the assumption
$[CH_{3}COOH]_{initial} = [CH_{3}COOH]_{equilibrium}$ can be made.

$k_{a} = [tex]= 1.8*10^{-5} = \frac{[H^{+}][CH_{3}COO^{-}]}{[CH_{3}COOH]} = \frac{0.001^{2}}{x}$

Solve for x to get the required concentration.

note: 1.)Since you need the answer in 2SF don&t round up values in the middle of the calculation like I've done here.

2.) The ICE (Initial, Change, Equilibrium) table may come in handy if you are new to problems of this kind

Hope this helps!

8 0

3 years ago

Of the following transitions in the Bohr hydrogen atom, the ________ transition results in the emission of the lowest-energy pho

Sladkaya [172]

N=6 ——> n=1
hope this helps!

5 0

3 years ago

Aqueous solutions of barium nitrate and potassium phosphate are mixed. What is the precipitate and how many molecules are formed

kykrilka [37]

Aqueous solutions of barium nitrate and potassium phosphate are mixed. What is the precipitate and how many molecules are formed?

Barium nitrate has a chemical symbol of Ba(NO3)2 and potassium phosphate has a chemical symbol K2PO4. The reaction between these two is a double replacement reaction yielding barium phosphate and potassium nitrate.

The chemical equation representing the reaction is,

Ba(NO3)2 + K2PO4 à KNO3 + BaPO4

8 0

3 years ago

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