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Vedmedyk [2.9K]
3 years ago
7

Which flow diagram best explains the energy transformations that occur within an automobile running on diesel

Chemistry
1 answer:
anyanavicka [17]3 years ago
5 0
In diesel engines, the chemical energy in the fuel is changed to heat energy, causing the pistons to expand via mechanical energy. The mechanical energy is finally converted to kinetic energy, which is observed as the movement of the vehicle.
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What characteristics of fish might allow them to survive
uranmaximum [27]
The fact that they lay like 300 eggs. And maybe that they are fast.
3 0
4 years ago
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Which of the following correctly summarizes the
Grace [21]

Answer:

A

Explanation:

The lithosphere represents the layer of hardened/solid rock that makes up the hard part of the earth, including the brittle upper portion of the mantle and the crust. The lithosphere is broken into pieces that are referred to as plates. The pieces move to and away from each other in a process known as plate tectonics. The movement of plates accounts for the global locations of volcanoes, earthquakes, and mountain ranges.

<em>The lithosphere is made of largely of inorganic materials known as silicates. The weathering of the solid rocks together with the interaction of living organisms gives rise to soil with an appreciable amount of organic materials.</em>

The correct option is, therefore A.

4 0
3 years ago
(6) Compare a CSTR with a PFR below. a. A flow of 0.3 m3/s enters a CSTR (volume of 200 m3) with an initial concentration of spe
Dmitry [639]

Answer:

Explanation:

Given that:

The flow rate Q = 0.3 m³/s

Volume (V) = 200 m³

Initial concentration C_o = 2.00 ms/l

reaction rate K = 5.09 hr⁻¹

Recall that:

time (t) = \dfrac{V}{Q}

time (t) = \dfrac{200}{0.3}

time (t) = 666.66 \ sec

time (t) = \dfrac{666.66 }{3600} hrs

time (t) = 0.185 hrs

\text{Using First Order Reaction:}

\dfrac{dc}{dt}=kc

where;

t = \dfrac{1}{k} \Big( \dfrac{C_o}{C_e}-1 \Big)

0.185 = \dfrac{1}{5.09} \Big ( \dfrac{200}{C_e}- 1 \Big)

0.942 =  \Big ( \dfrac{200}{C_e}- 1 \Big)

1+ 0.942 =  \Big ( \dfrac{200}{C_e} \Big)

\dfrac{200}{C_e} = 1.942

C_e = \dfrac{200}{1.942}

\mathbf{C_e = 102.98 \ mg/l}

Thus; the concentration of species in the reactant = 102.98 mg/l

b). If the plug flow reactor has the same efficiency as CSTR, Then:

t _{PFR} = \dfrac{1}{k} \Big [ In ( \dfrac{C_o}{C_e}) \Big ]

\dfrac{V_{PFR}}{Q_{PFR}} = \dfrac{1}{k} \Big [ In ( \dfrac{C_o}{C_e}) \Big ]

\dfrac{V_{PFR}}{Q_{PFR}} = \dfrac{1}{5.09} \Big [ In ( \dfrac{200}{102.96}) \Big ]

\dfrac{V_{PFR}}{Q_{PFR}} =0.196 \Big [ In ( 1.942) \Big ]

\dfrac{V_{PFR}}{Q_{PFR}} =0.196(0.663)

\dfrac{V_{PFR}}{0.3 hrs} =0.196(0.663)

\dfrac{V_{PFR}}{0.3*3600 sec} =0.196(0.663)

V_{PFR} =0.196(0.663)*0.3*3600

V_{PFR} = 140.34 \ m^3

The volume of the PFR is ≅ 140 m³

3 0
3 years ago
Question Ask “ Which Part Of The Ecological Pyramid Is Incorrect.”
shepuryov [24]
Primary producers i believe
4 0
3 years ago
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Xg of U and 3.795 g of O combine to form 20.00 g of
Deffense [45]

The percent composition of Uranium in U308 = C. 81.03%

<h3>Further explanation</h3>

Given

X g of U

3.795 g of O

20.00 g of  U308

Required

The percent composition of Uranium

Solution

mass of Uranium in U308 :

= mass of U308 - mass of O

= 20 g - 3.795 g

= 16.205 g

The percent composition :

\tt \%U=\dfrac{mass~U}{mass~U308}\times 100\%

%U = (mass U/mass U308) x 100%

%U= (16.205/20) x 100%

%U = 81.025≈81.03

8 0
3 years ago
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