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mario62 [17]
3 years ago
5

Roland is measuring a physical property of an object. He records the measurement:

Chemistry
1 answer:
Vsevolod [243]3 years ago
3 0

Answer:

The correct answer is density. See the explanation below, please.

Explanation:

Roland measured density, which is a property that relates mass to volume, having units for example: grams / cm3

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Which of the following is a unit of density? = Mass / volume
krok68 [10]

Answer:

The correct answer is C.

Explanation:

To solve this problem, we should first recall possible units for mass and volume.  Mass can be represented with units of grams, kilograms, etc.  Volume has units of cubic meters, cubic centimeters, etc.

Therefore, since we know that density is mass divided by volume, the only answer that makes sense here is C. grams per cubic centimeter (where per signifies that grams are being divided by cubic centimeters).

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2. A 10.0 g ice cube, initially at 0.0ºC, is melted in 100.0 g of water that was initially 20.0ºC. After the ice has melted, the
arlik [135]

Answer:

The heat lost  by the water  Q_{water}  = 3.8 KJ

The heat gain by ice  Q_{ice} = 228.76 J

The heat required to melt the ice Q_{melt} = 3340 J

Explanation:

Mass of ice cube m_{ice} = 10 gm

Initial temperature of ice cube T_{ice} = 0 °c

Mass of water m_{water} = 100 gm

Initial temperature of water T_{w} = 20 °c

Final temperature of mixture T_{f} = 10.93 °c

(a). Total heat lost by the water Q_{water}  =  m_{water} C_{w} ( T_{f} - T_{w} )

⇒ Q_{water}  = 100 × 4.184 (20 - 10.93)

⇒ Q_{water}  = 3.8 KJ

This is the heat lost  by the water.

(b). Heat gained by the ice cube Q_{ice} = m_{ice} C_{ice} (T_{f} - T_{ice}  )

⇒ Q_{ice} = 10 × 2.093 × ( 10.93 - 0)

⇒ Q_{ice} = 228.76 J

This is the heat gain by ice.

(C). Heat required to melt the ice Q_{melt} = m_{ice} × Latent Heat

⇒ Q_{melt} = 10 × 334

⇒ Q_{melt} = 3340 J

This is the heat required to melt the ice.

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