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Sergeu [11.5K]
3 years ago
7

consider this quadratic equation x2+2x+7=21 the nuber of positive solutions to this equation are blank. the approximate value of

the greatest solution to the equation, rounded to the nearest hundredth, is blank.​
Mathematics
1 answer:
S_A_V [24]3 years ago
6 0

Answer:

<em><u>x²</u></em><em><u>+</u></em><em><u>2</u></em><em><u>x</u></em><em><u>+</u></em><em><u>7</u></em><em><u>-</u></em><em><u>2</u></em><em><u>1</u></em><em><u>=</u></em><em><u>0</u></em>

<em><u> </u></em><em><u> </u></em><em><u>x²</u></em><em><u>+</u></em><em><u>2</u></em><em><u>x</u></em><em><u>-</u></em><em><u>1</u></em><em><u>4</u></em><em><u>. </u></em><em><u> </u></em><em><u>=</u></em><em><u>0</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>x²</u></em><em><u>+</u></em><em><u>2</u></em><em><u>x</u></em><em><u>. </u></em><em><u> </u></em><em><u>=</u></em><em><u>1</u></em><em><u>4</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>x²</u></em><em><u>+</u></em><em><u>2</u></em><em><u>x</u></em><em><u>+</u></em><em><u>1</u></em><em><u>. </u></em><em><u> </u></em><em><u>=</u></em><em><u>1</u></em><em><u>4</u></em><em><u>+</u></em><em><u>1</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>(</u></em><em><u>X+</u></em><em><u>1</u></em><em><u>)</u></em><em><u>²</u></em><em><u>. </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>=</u></em><em><u>1</u></em><em><u>5</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>X+</u></em><em><u>1</u></em><em><u>. </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>=</u></em><em><u>+</u></em><em><u>/</u></em><em><u>-</u></em><em><u>√</u></em><em><u>1</u></em><em><u>5</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>X=</u></em><em><u>-</u></em><em><u>1</u></em><em><u>+</u></em><em><u>/</u></em><em><u>-</u></em><em><u>√</u></em><em><u>1</u></em><em><u>5</u></em>

<em><u>X=</u></em><em><u>-</u></em><em><u>1</u></em><em><u>+</u></em><em><u>3.872983346207</u></em>

<em><u> </u></em><em><u> </u></em><em><u>=</u></em><em><u>2.872983346207</u></em><em><u>(</u></em><em><u>greate</u></em><em><u>st</u></em><em><u> </u></em><em><u>sol</u></em><em><u>ution</u></em><em><u>)</u></em><em><u> round</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>possible</u></em>

<em><u>X=</u></em><em><u>-</u></em><em><u>1</u></em><em><u>-</u></em><em><u>3.872983346207</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>=</u></em><em><u>-</u></em><em><u>4.872983346207</u></em>

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There are 25 $10 bills and 11 $20 bills.

Step-by-step explanation:

Given,

Worth of proceeds from garage = $470

Let,

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According to given situation;

10x+20y=470       Eqn 1

x = y+14                Eqn 2

Putting value of x from Eqn 2 in Eqn 1

10(y+14)+20y=470\\10y+140+20y=470\\30y=470-140\\30y=330

Dividing both sides by 30

\frac{30y}{30}=\frac{330}{30}\\y=11

Putting y=11 in Eqn 2

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There are 25 $10 bills and 11 $20 bills.

Keywords: linear equation, substitution method

Learn more about linear equations at:

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3 years ago
1/3k+80=1/2k+120 what does k equal?
LenaWriter [7]

Answer:

k = -1/240

Step-by-step explanation:

to evaluate the value of k in the expression 1/3k+80=1/2k+120

we have

1/3k+80=1/2k+120

collect the like terms for easy evaluation

1/3k - 1/2k = 120 -80

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therefore the value of k in the expression 1/3k+80=1/2k+120 is equals to -1/240

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The answer is (2,0)

Explanation

So I’m gonna use substitution to help me solve this problem. I’m gonna solve for x.

X-y=2

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Now that we have solved for x we are going to plug it into the first equation!
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Y+2 - 10y = 2

Then we solve it as a normal problem

So first we combine light terms

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Speed = 1000m/200s

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