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Elina [12.6K]
3 years ago
9

WILL GIVE BRAINLIEST AND 5 STARS what is the purpose/ use of a Bunsen Burner

Chemistry
2 answers:
Roman55 [17]3 years ago
5 0

A Bunsen burner, named after Robert Bunsen, is a common piece of laboratory equipment that produces a single open gas flame, which is used for heating, sterilization, and combustion. The gas can be natural gas (which is mainly methane) or a liquefied petroleum gas, such as propane, butane, or a mixture of both. Have A Great Day :)

ZanzabumX [31]3 years ago
4 0

Answer:

A Bunsen burner, named after Robert Bunsen, is a common piece of laboratory equipment that produces a single open gas flame, which is used for heating, sterilization, and combustion. The gas can be natural gas (which is mainly methane) or a liquefied petroleum gas, such as propane, butane, or a mixture of both.

Hope this helps yu!

n thanks if yu give brainliest!

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<em>Answer:</em>

  • It behaves as the electron donar. Its is correct one

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  • Lewis base is a such a substance which donate pair of electron to Lewis acid.

<em>Example:</em>

                                       H3N +  BF3  ⇒   H3N---≥BF3

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What is the new mass/volume percent (m/v) of a KOH solution that is prepared by diluting 110 mL of a 6.0% (m/v) KOH solution to
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Answer:

The new mass/volume percent is 2.0% (m/v)

Explanation:

Dilution is a procedure by which the concentration of a solution is decreased, generally with the addition of a diluent. In other words, dilution is a process in which a concentrated solution is always started, to which a greater volume of solvent is added, causing the concentration and volume of the resulting solution to change. But the amount of solute used to prepare the initial solution remains the same.

The calculation of a dilution is made by:

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In this case:

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  • Vinitial: 110 mL
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Replacing:

6.0% (m/v) * 110 mL= Cfinal* 330 mL

Solving:

Cfinal=\frac{ 6.0 (m/v)*110 mL}{330 mL}

Cfinal=   2.0% (m/v)

<u><em>The new mass/volume percent is 2.0% (m/v)</em></u>

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