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krok68 [10]
4 years ago
7

Is the boiling point of oxygen higher than nitrogen's

Chemistry
1 answer:
PSYCHO15rus [73]4 years ago
8 0
The boiling point of oxygen is higher than nitrogen's boiling The reason the boiling point of O2 is higher is not because of increased van der Waals interactions, but simple physics. The mass of a molecule of O2 is greater than that of a molecule of N2, so the molecule of O2 traveling at a speed sufficient to break out of the liquid phase has a greater kinetic energy than an analogous N2 molecule. The net effect is that more energy must be distributed throughout a sample of O2 to achieve a given vapor pressure (in this case equal to atmospheric pressure) than for a sample of N2. More energy means greater temperature.
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Calculate [H3O+] and [OH−] for each of the following solutions at 25 ∘C given the pH.<br> pH= 2.89
dimaraw [331]

Answer: The value of [H_{3}O^{+}] is 0.0012 M and [OH^{-}] is 1.02 \times 10^{-14}.

Explanation:

pH is the negative logarithm of concentration of hydrogen ion.

It is given that pH is 2.89. So, the value of concentration of hydrogen ions is calculated as follows.

pH = - log [H^{+}]\\2.89 = - log [H^{+}]\\conc. H^{+} = 0.0012 M

The relation between pH and pOH value is as follows.

pH + pOH = 14

0.0012 + pOH = 14

pOH = 14 - 0.0012 = 13.99

Now, pOH is the negative logarithm of concentration of hydroxide ions.

Hence, [OH^{-}] is calculated as follows.

pOH = - log [OH^{-}]\\13.99 = - log [OH^{-}]\\conc. OH^{-} = 1.02 \times 10^{-14} M

Thus, we can conclude that the value of [H_{3}O^{+}] is 0.0012 M and [OH^{-}] is 1.02 \times 10^{-14}.

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1. What mass of Mgo will I make from 48 g of Mg?<br> 2Mg + O2 + 2MgO
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Answer:

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