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Sav [38]
3 years ago
10

What Element is found in column 16, period 2?

Chemistry
2 answers:
Art [367]3 years ago
8 0
The answer is Sulfur.

Valentin [98]3 years ago
5 0
I thought it was Oxygen though???
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The table below shows two types of electromagnetic waves and three random applications of electromagnetic waves.
Reptile [31]
Correct Answer is 1 i.e. Gamma rays—2 and radio waves—3

Reason: 
1) In a hypernova, star<span> as similar to </span>nuclear fusion<span> converts lighter elements into heavy elements. If fusion is not capable of generating enough pressure to counteract gravity, star immediately collapses to form a </span>black hole<span>. During this process, energy will be released, along the axis of rotation to form </span>gamma-ray burst. Such gamma-ray burst was first detected using <span>Fermi Gamma-ray Space Telescope. Thus, gamma-ray is capable of providing information of gravity fields.

2) Radiowaves are capable of inducing transitions that requires less energies. These transition includes nuclear excitation and electron excitation (in rotational energy level). Depending upon the value to Jmax, it is possible to determine the temperature and </span><span>heat released by astronomical objects</span><span>
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4 0
3 years ago
Read 2 more answers
"the osmotic pressure exerted by a solution is equal to the molarity multiplied by the absolute temperature and the gas constant
ASHA 777 [7]

Answer: -

The concentration is 0.91 mol/ L

Explanation: -

The osmotic pressure = 23 atm

Absolute temperature = 309 K

Universal gas constant = 0.08206 L atm mol⁻¹ K⁻¹

We know the formula

Osmotic pressure = molar concentration x universal gas constant x absolute temperature

Plugging in the values

23 atm = molar concentration x 0.08206 L atm mol⁻¹ K⁻¹ x 309 K

Molar concentration = \frac{23}{0.08206 x 309} mol/ L

                                  = 0.91 mol / L

8 0
3 years ago
Read 2 more answers
O1S. Answer the following questions using Boyle's law:
Olenka [21]

Answer: 0.5 atm

Explanation:

you would want to use Boyles law which is P1P2=P2V2

or in this case, 1.00atm x 5.00L=P2 x 10.0L

                       1.00x5.00/10.00= 0.50atm

3 0
3 years ago
Please help me this is my fourth attempt.
Vaselesa [24]

Explanation:

CH4 + 4S ---> CS2 + 2H2S

4) 0.75 mol S × (1 mol CS2/4 mol S) = 0.19 mol CS2

5) 3 mol H2S × (1 mol CH4/2 mol H2S) = 1.5 mol CH4

Fe2O3 + 2Al ---> 2Fe + Al2O3

6) 25 g FeO3 × (1 mol Fe2O3/159.69 g Fe2O3) = 0.16 mol Fe2O3

0.16 mol Fe2O3 × (2 mol Al/1 mol Fe2O3) = 0.32 mol Al

0.32 mol Al × (26.98 g Al/1 mol Al) = 8.6 g Al

7) Given:

45 g Al × (1 mol Al/26.98 g Al) = 1.6 mol Al

85 g Fe2O3 ×(1 mol Fe2O3/159.69 g Fe2O3)

= 0.53 mol Fe2O3

Let's look at how much Fe each reactant will produce:

1.6 mol Al × (2 mol Fe/2 mol Al) = 1.6 mol Fe

0.53 mol Fe2O3 × (2 mol Fe/1 mol Fe2O3) = 1.1 mol Fe

Note that the given amount of Fe2O3 will give us fewer Fe. Therefore, Fe2O3 is the limiting reactant.

8) Al will produce 1.6 mol Fe × (55.845 g Fe/1 mol Fe)

= 89 g Fe

Fe2O3 will produce 1.1 mol Fe × (55.845 Fr/1 mol Fe)

= 61 g Fe

9) Since Fe2O3 is the limiting reactant, the ideal yield of Fe for the reaction is 61 g. If the actual reaction only gave us 25 g Fe. then the percent yield of Fe is

%yield = (25 g Fe/61 g Fe) × 100% = 41%

10) If we only got 25 g Fe, then the amount of Al actually used in the reaction is

25 g Fe × (1 mol Fe/55.845 g Fe) = 0.45 mol Fe

0.45 mol Fe × (2 mol Al/2 mol Fe) = 0.45 mol Al

0.45 mol Al × (26.98 g Al/1 mol Al) = 12 g

Therefore, the leftover amount of Al is

25 g Al - 12 g Al = 13 g Al

8 0
3 years ago
Need help I don't remember what to do?
Lina20 [59]
I'm just doing the ones that you don't have numbers already for.
2.) just leave it alone and it's correct
3.) Mg + 2AgNo3 --> Mg(No3)2 + 2Ag
5.) just leave it alone and it's correct
8.) 10C3H8O3 + 15O2 --> 30CO2 + 4H2O
10.) P4 + 6Br2 --> 4PBr3
12.) 2FeCl3 + 6NaOH --> 2Fe(OH)3 + 6NaCl
13.) 2CH3OH + 3O2 --> 2CO2 + 4H2O
14.) 2Al + 3Cu(NO3)2 --> 2Al(NO3)3 + 3Cu
15.) 3CaCl2 + 2K3AsO4 --> Ca3(AsO4)2 + 6KCl
16.) 2NH3 --> N2 + 3H2
17.) 2H3PO4 + 3Ba(OH)2 --> Ba3(PO4)2 + 6H2O
19.) Mg3N2 + 6H2O --> 3Mg(OH)2 + 2NH3
I hope this helps you!!
4 0
3 years ago
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