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goldfiish [28.3K]
3 years ago
10

Please help! trying to past :((

Chemistry
1 answer:
Margaret [11]3 years ago
3 0

the block will move to F but at the same time make it's way over to G because 250g weighs more than 100g

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Which reaction has the highest atom economy for the production of C02?​
In-s [12.5K]

The highest atom economy

2CO + O₂ ⇒ 2CO₂

<h3>Further explanation</h3>

Given

The reaction for the production of CO₂

Required

The highest atom economy

Solution

In reactions, there are sometimes unwanted products that can be said to be a by-product or a waste product. Meanwhile, the desired product can be said to be a useful product, which can be shown as the atom economy

of the reaction

the higher the atomic economy value of a reaction, the smaller the waste/ byproducts produced, so that less energy is wasted

The general formula:

Atom economy = (mass of useful product : mass of all reactants/products) x 100

<em>or </em>

Atom economy = (total formula masses of useful product : total formula masses of all reactants/products) x 100

So a reaction that only produces one product will have the highest atomic value, namely the reaction in option C

4 0
3 years ago
Which list of elements consists of a metal, a metalloid, and a nonmetal?
Irina18 [472]

Answer:

Sn, Si, C

Explanation:

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3 years ago
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attashe74 [19]
4. Static, sliding,rolling,and fluid friction
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3 years ago
Which statement defines specific heat capacity for given sample?
Aleks04 [339]

Answer:

D. the quantity of heat that is required to raise 1 g of the sample by 1*C (kelvin) at a constant pressure.

6 0
2 years ago
Read 2 more answers
On the basis of the information above, what is the approximate percent ionization of HNO2 in a 1.0 M HNO2 (aq) solution?
enot [183]

Answer:

The answer is "2%"

Explanation:

Equation:

HNO_2\ (aq) \leftrightharpoons  H^{+} \ (aq) + NO_2^{-}\ (aq) \\\\\  K_a = 4.0\times \ 10^{-4}

H^{+}=?

Formula:

Ka = \frac{[H^{+}][NO_2^{-}]}{[HNO_2]}

Let

[H^{+}] = [NO_2^{-}] = x at equilibrium

x^2 = (4.0\times 10^{-4})\times 1.0\\\\x = ((4.0\times 10^{-4})\times 1.0)^{0.5} = 2.0 \times 10^{-2} \  M\\\\

therefore,

[H^{+}] = 2.0\times 10^{-2} \ M = 0.02 \ M

Calculating the % ionization:

= \frac{([H^{+}]}{[HNO_2])} \times 100 \\\\= \frac{0.02}{1}\times 100 \\\\= 2\%\\\\

6 0
3 years ago
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