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alisha [4.7K]
3 years ago
12

2-1 help anyone pls............

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
3 0

Answer:

In what book?

Step-by-step explanation:

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What is the tan invers of 3i/-1-i​
postnew [5]

<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> )

<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> ) × (-1 + <em>i</em> ) / (-1 + <em>i</em> )

<em>z</em> = (3<em>i</em> × (-1 + <em>i</em> )) / ((-1)² - <em>i</em> ²)

<em>z</em> = (-3<em>i</em> + 3<em>i</em> ²) / ((-1)² - <em>i</em> ²)

<em>z</em> = (-3 - 3<em>i </em>) / (1 - (-1))

<em>z</em> = (-3 - 3<em>i </em>) / 2

Note that this number lies in the third quadrant of the complex plane, where both Re(<em>z</em>) and Im(<em>z</em>) are negative. But arctan only returns angles between -<em>π</em>/2 and <em>π</em>/2. So we have

arg(<em>z</em>) = arctan((-3/2)/(-3/2)) - <em>π</em>

arg(<em>z</em>) = arctan(1) - <em>π</em>

arg(<em>z</em>) = <em>π</em>/4 - <em>π</em>

arg(<em>z</em>) = -3<em>π</em>/4

where I'm taking arg(<em>z</em>) to have a range of -<em>π</em> < arg(<em>z</em>) ≤ <em>π</em>.

6 0
2 years ago
Hey i really need help with this. thank you:))
balandron [24]

Given:

L=2\dfrac{1}{2} ft and W=3\dfrac{2}{5} ft.

P=2L+2W

To find:

The value of P.

Solution:

We have,

P=2L+2W

Substituting L=2\dfrac{1}{2} and W=3\dfrac{2}{5}, we get

P=2\times 2\dfrac{1}{2}+2\times 3\dfrac{2}{5}

P=2\times \dfrac{2(2)+1}{2}+2\times \dfrac{3(5)+2}{5}

P=2\times \dfrac{5}{2}+2\times \dfrac{17}{5}

P=5+\dfrac{34}{5}

Taking LCM, we get

P=\dfrac{5(5)+34}{5}

P=\dfrac{25+34}{5}

P=\dfrac{59}{5}

P=11\dfrac{4}{5}

Therefore, the value of P is 11\dfrac{4}{5} ft.

7 0
3 years ago
Am I the only one whose parents yell their name and when you tell back yes mom they don’t answer?
arsen [322]
No your not the only one
6 0
3 years ago
Read 2 more answers
Given y = log3(x + 4), what is the domain?
dem82 [27]
For a logarithmic function, we have a restriction on the domain.
Since log(0) isn't defined, we say that there is an asymptote at x = 0.
Thus, for the regular logarithmic function y = log(x), x > 0.

We can then say (x + 4) > 0, since that's when the function of a logarithm is defined as.
x + 4 > 0
x > -4

Thus, the domain of the logarithmic function is x > -4, where x is a real integer.
5 0
3 years ago
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What is greater one seventh or one nineth
Anton [14]

Method 1:

Look at the picture.

\dfrac{1}{7} is greater than \dfrac{1}{9}

\boxed{\dfrac{1}{7}>\dfrac{1}{9}}

Method 2:

Find the common denominator:

multiples of 7: 0, 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, ...

multiples of 9: 0, 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, ...

63 = 7 · 9

\dfrac{1}{7}=\dfrac{1\cdot9}{7\cdot9}=\dfrac{9}{63}\\\\\dfrac{1}{9}=\dfrac{1\cdot7}{9\cdot7}=\dfrac{7}{63}

\dfrac{9}{63} > \dfrac{7}{63}

therefore

\dfrac{1}{7} > \dfrac{1}{9}

3 0
3 years ago
Read 2 more answers
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