Answer:
All of the above are involved in moving water up to the branches and leaves
Answer:
See the answer below
Explanation:
<em>Recall that the law of dilution states that the number of moles before dilution must be equal to the number of moles after dilution.</em>
Mathematically,
molarity x number of moles before dilution = molarity x number of moles after dilution.
For solution A: final molarity = 3 mM, final volume = 2mL, initial molarity of KMnO4 = 10 mM
Applying the equation:
10 x initial volume = 3 x 2
initial volume = 6/10 = 0.6
<u>Hence, Tube A should be made with 0.6 mL of 10 mM KMnO4 stock and 1.4 mL of distilled water to give a solution of 2 mL 3 mM KMnO4.</u>
For solution B:final molarity = 8 mM, final volume = 2 mL, initial molarity = 10 mM
10 x initial volume = 8 x 2
initial volume = 16/10 = 1.6
<u>Hence, Tube B should be made with 1.6 mL of 10 mM KMnO4 stock and 0.4 mL of distilled water to give a solution of 2 mL 8mM KMnO4. </u>
Individuals with glucose-6-phosphate dehydrogenase deficiency have increased resistance to malaria because the parasite does not survive well in cells with oxidative stress.
<h3>What is the link between G6P deficiency and malaria?</h3>
- Glucose-6-phosphate dehydrogenase (G6PD) deficiency is an X-linked recessive disorder.
- G6PD protects cells from oxidative damage especially the RBCs whose main function is to carry oxygen.
- Mutation in the gene results in G6PD deficiency leading to oxidative stress which can lead to anemia (iron deficiency) as there is breakdown of RBCs.
- However, G6PD deficiency is quite common in parts of Africa, Middle East, and South Asia, which are the regions of high malaria endemism.
- This is due to natural selection in which G6PD deficiency is not eliminated from the population as it can protect people from malaria infection.
- Malaria parasite <em>Plasmodium</em> species does not survive well in cells with oxidative stress.
Learn about malaria here:
brainly.com/question/17033567
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