Someone pls help :(

What is an equation of a line with the given slope and y-intercept.<br><br> m = 2, b = 6

Schach [20]

Answer:

Slope intercept form is y=2x+b

Step-by-step explanation:

5 0

3 years ago

Use Lagrange multipliers to find the maximum and minimum values of the function subject to the given constraint. (If an answer d

andrey2020 [161]

Answer:

The maximum value is 1/27 and the minimum value is 0.

Step-by-step explanation:

Note that the given function is equal to $(xyz)^2$ then it means that it is positive i.e $f(x,y,z)\geq 0$ .

Consider the function $F(x,y,z,\lambda)=x^2y^2z^2-\lambda (x^2+y^2+z^2-1)$

We want that the gradient of this function is equal to zero. That is (the calculations in between are omitted)

$\frac{\partial F}{\partial x} = 2x(y^2z^2 - \lambda)=0$

$\frac{\partial F}{\partial y} = 2y(x^2z^2 - \lambda)=0$

$\frac{\partial F}{\partial z} = 2z(x^2y^2 - \lambda)=0$

$\frac{\partial F}{\partial \lambda} = (x^2+y^2+z^2-1)=0$

Note that the last equation is our restriction. The restriction guarantees us that at least one of the variables is non-zero. We've got 3 options, either 1, 2 or none of them are zero.

If any of them is zero, we have that the value of the original function is 0. We just need to check that there exists a value for lambda.

Suppose that x is zero. Then, from the second and third equation we have that

$-2y\lambda = -2z\lambda$ . If lambda is not zero, then y =z. But, since $-2y\lambda=0$ and lambda is not zero, this implies that x=y=z=0 which is not possible. This proofs that if one of the variables is 0, then lambda is zero. So, having one or two variables equal to zero are feasible solutions for the problem.

Suppose that only x is zero, then we have the solution set $y^2+z^2=1$ .

If both x,y are zero, then we have the solution set $z^2=1$ . We can find the different solution sets by choosing the variables that are set to zero.

NOw, suppose that none of the variables are zero.

From the first and second equation we have that

$\lambda = y^2z^2 = x^2z^2$ which implies $x^2=y^2$

Also, from the first and third equation we have that

$\lambda = y^2z^2 = x^2y^2$ which implies $x^2=z^2$

So, in this case, replacing this in the restriction we have $3z^2=1$ , which gives as another solution set. On this set, we have $x^2=y^2=z^2=\frac{1}{3}$ . Over this solution set, we have that the value of our function is $\frac{1}{3^3}= \frac{1}{27}$

4 0

3 years ago

24 cm ,18cm ,c <br> We are looking for c

Ierofanga [76]

Step-by-step explanation:

we can find the value of c by Pythagoras theorem

according to Pythagoras theorem

h² = a² + b²

where

h = hypotenuse (i.e. longest side of a right angled triangle)

a = side

b = base

so, we have to find h or hypotenuse here

h² = (24)² + (18)²

h = 576 + 324 = 900

h² = √900 = 30

c = 30

therefore, value of c is 30.

Hope this answer helps you dear!

3 0

2 years ago

What is the number for thirty-nine million five thousand in standard form

hammer [34]

395,000,000 i think not sure

5 0

3 years ago

1. PLEASE HELP. Consider the matrices-

Alex

Answer:

A - B = [ -1 3 ]

[ -6 2 ]

[ -4 -10 ]

Step-by-step explanation:

Since Matrix A and Matrix B have the same size, then we can simply perform the operation of subtraction on each position within the matrices to get the resulting subtracted matrix.

A = [ 4 7 ] B = [ 5 4 ]

[ -3 8 ] [ 3 6 ]

[ -5 -2 ] [ -1 8 ]

A - B = [ (4 - 5) (7 - 4) ]

[ (-3 - 3) (8 - 6) ]

[ (-5 - -1) (-2 - 8) ]

A - B = [ -1 3 ]

[ -6 2 ]

[ -4 -10 ]

Cheers.

8 0

3 years ago