Answer:
e=0.374V
Explanation:
the induced voltage is the work done per unit of charge. Hence we have
however, the angle between the piece of conductor and the field is 0°. Hence
THE INDUCED VOLTAGE IS 0.374V
hope this helps!!
Answer:
The net force acting on the otter along the incline is 13.96 N.
Explanation:
It is given that,
Mass of the otter, m = 2 kg
Distance covered by otter, d = 85 cm = 0.85 m
It takes 0.5 seconds.
We need to find the net force acts on the otter along the incline. If a is the acceleration of the otter. It can be calculated using second equation of motion as :
Here, u = 0 (at rest)
The net force acting on the otter along the incline is given by :
F = ma
F = 13.6 N
So, the net force acting on the otter along the incline is 13.96 N. Hence, this is the required solution.
Answer:
+Q
Explanation:
As no electric field can exist (in electrostatic condition) inside a conductor, if we apply Gauss 'Law to a spherical gaussian surface with a radius just a bit larger than the distance of the inner surface to the center (but less tah the distance of the outer surface), the net flux through this surface must be zero, due to E=0 at any point of the gaussian surface.
Therefore, as the net flux must be proportional to the charge enclosed by the surface, it follows that Qenc = 0.
⇒ Qenc = Qc + Qin = -2Q + Qin = 0 ⇒ Qin = +2Q
So, if the net charge of the conductor is + 3Q (which must remain the same due to the conservation of charge principle) and no charge can exist within the conductor (in electrostatic conditions), we have the following equation:
Qnet = Qin + Qou = +3Q ⇒ +2Q + Qou = +3Q
⇒ Qou = +Q
Explanation:
The given data is as follows.
mass (m) = 5 kg
Height of tower = 15 m
u = 7 m/s
air resistance = 610 v
(a) Now, differential equation for the given mass which is thrown vertically upwards is as follows.
= F
-bv = Fr
Here, mg is downwards due to the force of gravity.
= 0
Hence, the differential equation required to solve the problem is as follows.
= 0
(b) When final velocity of the object is equal to zero then the object will reach towards its maximum height and it will start to fall downwards.
F =
= 0
Therefore, the object reach its maximum height at v = 0.
The canoe's KE is 200 'cause you have to multiply the mass to the squared(times itself) velocity and once you got the product, divide it by 2