Question

WILL GIVE BRAINLIEST AND 30 POINTS!

Answer 1

Answer:

1. B. Increase

2. A. Decrease

Explanation:

To understand this issue, we need to put some values and using the ohm's law we can corroborate the two situations.

Ohm's law:

$V = I*R\\where:\\I = current[A] ampers\\R = resistance [ohms]\\V = voltage [volts]$

Now for the voltage we will use V = 110 [V], for resistance R = 10 [ohms]

Replacing the values we have:

$I = \frac{V}{R} \\\\I = \frac{110}{10}\\I= 11 [amp]$

Now let's double the voltage 220 [V]:

$I = \frac{220}{10} \\I = 22 [amp]$

Therefore the current will be increased.

Let's do the same for the resistance if originally we have R = 10 [ohms]

$I = \frac{V}{R}\\I = \frac{110}{10} \\I = 11 [amp]$

Now let's double the resistance 20 [ohms]:

$I=\frac{110}{20}\\I = 5.5 [amp]$

Therefore the current will be decreased.