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julia-pushkina [17]
3 years ago
7

What mass of a material with density rho is required to make a hollow spherical shell having inner radius r1 and outer radius r2

? (Use any variable or symbol stated above as necessary.)
Physics
1 answer:
satela [25.4K]3 years ago
8 0

Answer:

\frac{4}{3}\rho\pi(r_2^3 - r_1^3)

Explanation:

The volume of the shell is the difference between the volume of the outer sphere and the volume of the inner sphere

V = V_o - V_i = \frac{4}{3}\pi r_2^3 - \frac{4}{3}\pi r_1^3

V = \frac{4}{3}\pi(r_2^3 - r_1^3)

The mass of the shell is the product of the volume and its density

m = V\rho = \frac{4}{3}\rho\pi(r_2^3 - r_1^3)

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Calculate the amount of work done to draw a current of 8A from a point at 100V to a point at 120V in 2 seconds?
Morgarella [4.7K]
Given:
I=8A
t=2second
Potential difference,V=120-100=20volt
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=20×8×2
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3 0
3 years ago
A weightlifter completes a series of lifts with a 700 N weight. In one lift, he raises the weight to a height of 2.5 m off the g
zhannawk [14.2K]

Answer:

The output power the weightlifter is 2916.67 W.

Explanation:

Given;

weight lifted, W = 700 N

height the weight is lifted, h = 2.5 m

time taken to lift the weight, t = 0.60 s

The output power the weightlifter is calculated as;

Power = Energy applied / time taken

Energy applied = weight lifted x height the weight is lifted

Energy applied = 700 x 2.5

Energy applied = 1750 J

Power = 1750 / 0.6

Power = 2916.67 J/s = 2916.67 W.

Therefore, the output power the weightlifter is 2916.67 W.

5 0
3 years ago
How much energy is required to move 2 electrons through a potential difference of 1.0 x 10^ 2 volts?
Ksenya-84 [330]
Charge of electron = 1.6×10−¹⁹

(1.6×10−¹⁹)(1×10²) (2e)

= 3.2×10−¹⁷ J
3 0
3 years ago
A small ball of mass 2.00 kilograms is moving at a velocity 1.50 meters/second. It hits a larger, stationary ball of mass 5.00 k
rewona [7]

The kinetic energy of the small ball before the collision is

                             KE  =  (1/2) (mass) (speed)²

                                     = (1/2) (2 kg) (1.5 m/s)

                                     =    (1 kg)  (2.25 m²/s²)

                                     =        2.25 joules.

Now is a good time to review the Law of Conservation of Energy:

                     Energy is never created or destroyed. 
                     If it seems that some energy disappeared,
                     it actually had to go somewhere.
                     And if it seems like some energy magically appeared,
                     it actually had to come from somewhere.

The small ball has 2.25 joules of kinetic energy before the collision.
If the small ball doesn't have a jet engine on it or a hamster inside,
and does not stop briefly to eat spinach, then there won't be any
more kinetic energy than that after the collision.  The large ball
and the small ball will just have to share the same 2.25 joules.

3 0
3 years ago
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