The number of nuclei that have decayed after three half-lives is 12.5% of the original mass.
<h3>
What is half live of radioactive isotope?</h3>
The half life of a radioactive isotope is the time taken for the element to decay to half of its original mass.
<h3>Number of nuclei decayed after 3 half lives</h3>
N = N₀/(2³)
N = N₀/8
N = 0.125N₀
N = 12.5% of N₀
where;
- N is n number of nuclei that have decayed after 3 half lives
- N₀ is the original mass
Thus, the number of nuclei that have decayed after three half-lives is 12.5% of the original mass.
Learn more about half life here: brainly.com/question/10525285
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The energy stored in the chemical bonds are released and the energy causes surrounding molecules to move faster. Chemical energy released as the coal is burned heats water and turns it to steam
Simple cellll importable
Ikr
Answer:
Explanation:
Answer:
repulsion force es R = 5,224 10⁻³ N
Explanation:
We use Newton's second law to add forces, the elective force is repulsive because the asteroids have the same type of charge and gravitational force is always attractive.
Gravitational force
Fg = G m1 m2 / r²
Fg = 6,673 10⁻¹¹ 5.7 10⁴ 5.5 10⁴/190²
Fg = 5,795 10⁻⁶ N
Electric force
Fe = k q1 q2 / r²
Fe = 8.99 10⁹ 14.0 10⁻⁶ 15.0 10⁻⁶ / 190²
Fe = 5.2296 10⁻³ N
The resulting force is
R = Fe - Fg
R = 5.2296 10⁻³ - 5.795 10⁻⁶= 5229.6 10⁻⁶ - 5,795 10⁻⁶
R = 5,224 10⁻³ N
this is a repulsive force and the asteroids move away from each other
Answer:
a) Tc = 750 [N] ;b) See the explanation below.
Explanation:
To solve this problem, we first need a graphical explanation of this, as well as knowing the corresponding questions. Therefore, a search was carried out in google, in the attached image we will find a graphical description of the problem.
b)
The solution of this type of problem corresponds to the use of Newton's third law, applying static which tells us that the sum of the forces in a system in equilibrium without movement must be equal to zero.
a)
In this way we can find by means of a sum of forces on the y axis equal to zero:
- 850 - 450 + 550 + Tc = 0
Tc = 750 [N]
